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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 5:INTRODUCTION TO THERMAL POWER PLANT"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex5.1:pg-271"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"\n",
"The coal required per hour,W= 50.95 tons/hr\n"
]
}
],
"source": [
"# Example 5_1\n",
" \n",
"# Given data\n",
"P=100.0;# Plant capacity in Mw\n",
"CV=25600.0;# Calorific value in kJ/kg\n",
"n_th=30.0;# The thermal efficiency of the plant in %\n",
"n_eg=92.0;# Electrical generation efficiency in %\n",
"\n",
"# Calculation\n",
"# Mechanical energy available=W*CV*(n_th/100) in kJ/hr\n",
"# Electrical energy available=W*CV*(n_th/100)*(n_eg/100) in kJ/hr\n",
"q_e=P*10**3*3600;# Heat equivalent in kJ/hr\n",
"W=(q_e/(CV*(n_th/100)*(n_eg/100)));# The coal required per hour in kg/hr\n",
"W=(W/1000);# The coal required per hour in tons/hr\n",
"print \"\\nThe coal required per hour,W=\",round(W,2),\" tons/hr\"\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex5.2:pg-273"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"\n",
" The capacity of the power plant,P= 62.05 MW\n"
]
}
],
"source": [
"# Example 5_2\n",
" \n",
"# Given data\n",
"CV=28900.0;#kJ/kg\n",
"n_b=83.0;# The boiler efficiency in %\n",
"n_t=32.0;# The turbine efficiency in %\n",
"n_g=97.0;# The generator efficiency in %\n",
"W=30.0;# The coal consumption of the station in tons/hr\n",
"\n",
"# Calculation\n",
"P=((W*1000*CV)*(n_b/100)*(n_t/100)*(n_g/100))/(3600*1000);# The capacity of the power plant in MW\n",
"print \"\\n The capacity of the power plant,P=\",round(P,2),\" MW\"\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex5.3:pg-273"
]
},
{
"cell_type": "code",
"execution_count": 8,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The volume of gas required per hour,V= 450.0 m**3/hr\n"
]
}
],
"source": [
"#Example 5_3\n",
"\n",
"# Given values\n",
"P=100.0;# Power in kW\n",
"CV=4000.0;# Calorific value in kJ/m**3\n",
"n_o=0.20;# Over all efficiency of the plant\n",
"\n",
"# Calculation\n",
"V=(3600*P)/(CV*n_o);# m**3/hr\n",
"print \"The volume of gas required per hour,V=\",round(V,2),\" m**3/hr\"\n"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 2",
"language": "python",
"name": "python2"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 2
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython2",
"version": "2.7.11"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|
