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{
"metadata": {
"celltoolbar": "Raw Cell Format",
"name": "",
"signature": "sha256:ef32575f9668e7c75384fec9d19e3d17f6260e600de2d26c9157520e2a39253b"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"ELEMENTS OF CHEMICAL ENGINEERING BY H.S. FOGLER"
]
},
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"CHAPTER NUMBER 1 : MOLE BALANCES"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"EXAMPLE NUMBER 1.3"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"k = 0.23; #min**-1\n",
"v0 = 10;#dm**3/min\n",
"#CA = 0.1*CA0;\n",
"V = (v0/k)*math.log(1/0.1);\n",
"print \"V =\",round(V,4),\"dm**3\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"V = 100.1124 dm**3\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"CHAPTER NUMBER 2 : CONVERSION AND REACTOR SIZING"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"EXAMPLE NUMBER 2.1"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" \n",
"import math\n",
" \n",
"P0 = 10; #atm\n",
"yA0 = 0.5;\n",
"T0 = 422.2;#K\n",
"R = 0.082;# dm**3.atm/mol.K\n",
"v0 = 6;#dm**3/s\n",
"CA0=(yA0*P0)/(R*T0);\n",
"FA0 = CA0*v0;\n",
"print \"CA0 =\",round(CA0,4),\"mol/dm**3\"\n",
"print \"FA0 =\",round(FA0,4),\"mol/s\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"CA0 = 0.1444 mol/dm**3\n",
"FA0 = 0.8665 mol/s\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"EXAMPLE NUMBER 2.2"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"P0 = 10; #atm\n",
"yA0 = 0.5;\n",
"T0 = 422.2;#K\n",
"R = 0.082;# dm**3.atm/mol.K\n",
"v0 = 6;#dm**3/s\n",
"X = 0.8;\n",
"rA = -1/800;#1/-rA = 800#dm**3.s/mol\n",
"CA0=(yA0*P0)/(R*T0);\n",
"FA0 = CA0*v0;\n",
"V = FA0*X*(1/-rA)\n",
"print \"FA0 =\",round(FA0,4),\"mol/s\"\n",
"print \"V =\",round(V,4),\"dm**3\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"FA0 = 0.8665 mol/s\n",
"V = 0.6932 dm**3\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"EXAMPLE NUMBER 2.3"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
" \n",
"P0 = 10; #atm\n",
"yA0 = 0.5;\n",
"T0 = 422.2;#K\n",
"R = 0.082;# dm**3.atm/mol.K\n",
"v0 = 6;#dm**3/s\n",
"X = [0,0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8];\n",
"p = [189,192,200,222,250,303,400,556,800];#1/-rA = 800#dm**3.s/mols\n",
"CA0=(yA0*P0)/(R*T0);\n",
"FA0 = CA0*v0;\n",
"#V = FA0*X*(1/-rA)\n",
"\n",
"V = FA0*np.interp(0.42,X,p)\n",
"print \"FA0 =\",FA0,\"mol/s\"\n",
"print \"V =\",V,\"dm**3\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"FA0 = 0.866541114487 mol/s\n",
"V = 225.820614435 dm**3\n"
]
}
],
"prompt_number": 21
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"EXAMPLE NUMBER 2.4"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"FA0 = 5; # mol/s\n",
"rAat=-0.0025;\n",
"X = [0,0.1,0.2,0.3,0.4,0.5,0.6];\n",
"p = [189,192,200,222,250,303,400];#1/-rA = 800#dm**3.s/mols\n",
"\n",
"VCSTR = FA0*X[6]*(1/-rAat);\n",
"VPFR = FA0*np.interp(0.00017,X,p)\n",
"print \"VCSTR =\",VCSTR,\"dm**3\"\n",
"print \"VPFR =\",VPFR,\"dm**3\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"VCSTR = 1200.0 dm**3\n",
"VPFR = 945.0255 dm**3\n"
]
}
],
"prompt_number": 37
}
],
"metadata": {}
}
]
}
|
