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{
"metadata": {
"name": "",
"signature": "sha256:b6d6dfa593701249cd6d305eb45cecde030c3502c19d325045b7e05cf46a035c"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"3: Atomic models"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.1, Page number 45"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"N=6.02*10**23; #avagadro number(atoms/mole)\n",
"rho=19.3; #density(g/cc)\n",
"A=197; #atomic weight(g)\n",
"k=8.984*10**9; #value of k(Nm**2/C**2)\n",
"Z=79;\n",
"Zdash=2;\n",
"e=1.6*10**-19; #conversion factor from J to eV\n",
"m=2;\n",
"v0=8*10**6; \n",
"t=2*10**-6; #thickness(m)\n",
"\n",
"#Calculation\n",
"n=N*rho*10**6/A; #number of atoms(per m**3)\n",
"b=k*Z*Zdash*e/(m*v0); #impact parameter(m)\n",
"f=math.pi*b**2*n*t; #fraction of particles scattered\n",
"\n",
"#Result\n",
"print \"fraction of particles scattered is\",round(f*10**5,1),\"*10**-5\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"fraction of particles scattered is 7.5 *10**-5\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.3, Page number 48"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"h=6.626*10**-34; #planck's constant(Js)\n",
"c=3*10**8; #velocity of light(m/sec)\n",
"e=1.6*10**-19; #conversion factor from J to eV\n",
"E=10.5; #energy(eV)\n",
"\n",
"#Calculation\n",
"E=(13.6+E)*e; #energy of photon(J)\n",
"lamda=h*c/E; #wavelength(m)\n",
"\n",
"#Result\n",
"print \"wavelength of photon is\",round(lamda*10**9,2),\"nm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"wavelength of photon is 51.55 nm\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.4, Page number 49"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"k=8.98*10**9; #value of k(Nm**2/C**2)\n",
"e=1.6*10**-19; #conversion factor from J to eV\n",
"n=1; #assume\n",
"a0=0.53*10**-10; #radius of orbit(m)\n",
"\n",
"#Calculation\n",
"PE=-k*(e**2)/(a0*e*n**2); #potential energy(eV)\n",
"E=-13.6/n**2; #energy(eV)\n",
"KE=E-PE; #kinetic energy(eV)\n",
"\n",
"#Result\n",
"print \"kinetic energy is\",round(KE,1),\"/n**2 eV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"kinetic energy is 13.5 /n**2 eV\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 3.6, Page number 51"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"Mbyme=1836; \n",
"lamda=6562.8; #wavelength for hydrogen(angstrom)\n",
"\n",
"#Calculation\n",
"mew_dashbymew=2*(1+Mbyme)/(1+(2*Mbyme));\n",
"lamda_dash=lamda/mew_dashbymew; #wavelength for deuterium(angstrom)\n",
"\n",
"#Result\n",
"print \"wavelength for deuterium is\",int(lamda_dash),\"angstrom\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"wavelength for deuterium is 6561 angstrom\n"
]
}
],
"prompt_number": 14
}
],
"metadata": {}
}
]
}
|
