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{
"metadata": {
"name": "",
"signature": "sha256:42c32bb83042eba762c882953210b5f735a47b1ef07c7eade0266ced5fe417ef"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 7 : Rainfall and Runoff"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7.5 Page No : 7-15"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\t\n",
"#initialisation of variables\n",
"n = 20. \t#ft\n",
"s = math.sqrt(12676/19.)\t#ft\n",
"c = 45.5\t#ft\n",
"q = 551400\t#ft\n",
"q1 = 12700\t#ft\n",
"h = 8.5\t#ft\n",
"w = s/c\t#ft\n",
"\t\n",
"#CALCULATIONS\n",
"D = q/(2*s*q1)\t#cfs\n",
"D1 = D*(1+h/n)\t#cfs\n",
"\t\n",
"#RESULTS\n",
"print 'the record runoff of a stream draining = %.2f cfs'%(D1)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the record runoff of a stream draining = 1.20 cfs\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7.6 Page No : 7-19"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\t\n",
"#initialisation of variables\n",
"i = 16./(62)**0.66\t#in hr\n",
"q = (16*10**0.31)/(62)**0.66\t#in hr\n",
"c = 1.0\t#max\n",
"C1 = c*(0.01)**0.31\t#in\n",
"C2 = c*(0.1)**0.31\t#in\n",
"x1 = 640\t#cfs\n",
"\t\n",
"#CALCULATIONS\n",
"Y1 = C1*i*c*x1\t#cfs\n",
"Y2 = C2*q*c*x1\t#cfs\n",
"\t\n",
"#RESULTS\n",
"print 'the time of concentration = %.f cfs'%(Y2)\n",
"\n",
"# rounding off error."
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the time of concentration = 672 cfs\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7.8 Page No : 7-25"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\t\n",
"#initialisation of variables\n",
"d = 163*48.5\t#cfs\n",
"a = 48.5\t#ft\n",
"q = 100\t#cfs\n",
"Q = 45.5*a\t#cfs\n",
"c = 0.57\t#cfs\n",
"v = 1.8\t#cfs\n",
"p = 0.45\t#ft\n",
"\t\n",
"#CALCULATIONS\n",
"P = d/(q*math.sqrt(a))\t#percent\n",
"C = Q/(a**0.8*(1+2*a**-0.3))\t#cfs\n",
"d1 = 2.6\t#cfs\n",
"T = (1-p*c+v*c*2)\t#cfs\n",
"\t\n",
"#RESULTS\n",
"print 'the meyers rating = %.1f percent'%(P)\n",
"print 'the magnitude of the maximum peak flood = %.1f cfs'%(T)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the meyers rating = 11.4 percent\n",
"the magnitude of the maximum peak flood = 2.8 cfs\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
