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{
"metadata": {
"name": "",
"signature": "sha256:d97ef885e741db81adc7f9703c96d41639df30eb154ebfc4a587f4f7ba56c3d8"
},
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 11 : Surface-Water Collection"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.1 Page No : 11-20"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\t\n",
"#initialisation of variables\n",
"s = 20.\t#mph\n",
"t = 90.\t#min\n",
"w = 1.31\t#ft\n",
"h = 7.5\t#miles\n",
"h1 = 0.22\t#ft\n",
"t1 = 1100.\t#min\n",
"t2 = 6.0\t#min\n",
"p = 32.2\t#ft\n",
"l = 5.12\t#length\n",
"l1 = 2.8\t#length\n",
"p1 = 1400.\t#ft\n",
"d = 73.\t#depth\n",
"h3 = 2.06\t#ft\n",
"e = 173.0\t#ft\n",
"hi = 0.2\t#ft\n",
"\t\n",
"#CALCULATIONS\n",
"W = s*w\t#mph\n",
"hs = h1*((W)**2/p)**0.53*h**0.47\t#ft\n",
"Ts = t2*(W/p)**0.44*(h/p)**0.28\t#sec\n",
"Td = t1*h/(p*Ts)\t#min\n",
"Ls = l1/(l*(Ts)**2)\t#ft\n",
"D = d/(l*(Ts)**2)\t#ft\n",
"H = (W)**2*(h*(1/(p1*d)))\t#ft\n",
"hr = h3*l1\t#ft\n",
"M = e+hi+hr\t#ft\n",
"\t\n",
"#RESULTS\n",
"print 'the overwater wind speed = %.0f mph'%(W)\n",
"print 'the significant wave height = %.1f ft'%(hs)\n",
"print 'the significant wave period = %.1f sec'%(Ts)\n",
"print 'the minimum wind duration required to reach the significant wave height = %.0f min'%(Td)\n",
"print 'the significant wave lenght adn steepness = %.3f ft'%(Ls)\n",
"print 'the reservoir depth ratio = %.1f ft'%(D)\n",
"print 'the wind tide or set up = % f ft'%(H)\n",
"print 'the run up = %.1f ft'%(hr)\n",
"print 'the maximum elevation reached by the waves = %.1f ft'%(M)\n",
"\n",
"# rounding off error. please check."
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the overwater wind speed = 26 mph\n",
"the significant wave height = 2.9 ft\n",
"the significant wave period = 3.6 sec\n",
"the minimum wind duration required to reach the significant wave height = 70 min\n",
"the significant wave lenght adn steepness = 0.041 ft\n",
"the reservoir depth ratio = 1.1 ft\n",
"the wind tide or set up = 0.050375 ft\n",
"the run up = 5.8 ft\n",
"the maximum elevation reached by the waves = 179.0 ft\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.2 Page No : 11-23"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\t\n",
"#initialisation of variables\n",
"g = 264\t#quartz\n",
"p = 0.39\t#percent\n",
"\t\n",
"#CALCULATIONS\n",
"S = (1-p)*(g-1)\t#in\n",
"\t\n",
"#RESULTS\n",
"print 'the hydraulic gradient and seepage velocity = %.2f in'%(S)\n",
"#incorrect answer in textbook"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the hydraulic gradient and seepage velocity = 160.43 in\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.3 Page No : 11-26"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\t\n",
"#initialisation of variables\n",
"w = 40\t#ft\n",
"k = 2*10**-3\t#cm/sec\n",
"p = 3.28*10**-3\t#cfs\n",
"h = 6.47*10**5\t#gpd\n",
"p1 = 0.433\t#ft\n",
"m = 9\t#ft\n",
"delh = w/(18*9)\t#in\n",
"k1 = 4.94*10**-4\t#cm/sec\n",
"\t\n",
"#CALCULATIONS\n",
"Q = k*p*w*(9./18)\t#cfs\n",
"Q1 = Q*h\t#gpd/ft width\n",
"P = (1-8./18)*w*p1\t#Psig\n",
"H = k1/k\t#in\n",
"\t\n",
"#RESULTS\n",
"print 'the seepage through each foot width of the foundation = %.0f gpd/ft/ width'%(Q1*10)\n",
"print 'the excess hydrostatic pressure on the upstream side of the bottom of the sheet pilling = %.2f Psig'%(P)\n",
"print 'the maximum hydraulic gradient and its relations to the coeeficent = %.2f in'%(H)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the seepage through each foot width of the foundation = 849 gpd/ft/ width\n",
"the excess hydrostatic pressure on the upstream side of the bottom of the sheet pilling = 9.62 Psig\n",
"the maximum hydraulic gradient and its relations to the coeeficent = 0.25 in\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.4 Page No : 11-13"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\t\n",
"#initialisation of variables\n",
"d = 120\t#ft\n",
"w = 16\t#ft\n",
"d1 = 120/0.8\t#ft\n",
"p = 60*0.8\t#ft\n",
"h = 2\t#ft\n",
"v = 18.74*0.8\t#ft\n",
"s = 95.23\t#ft\n",
"s1 = 0.8\t#ft\n",
"\t\n",
"#CALCULATIONS\n",
"W = d-h*p\t#ft\n",
"S = s*s1\t#ft\n",
"\t\n",
"#RESULTS\n",
"print 'in succession from the intersection of the upstream slop = %.2f ft'%(S)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"in succession from the intersection of the upstream slop = 76.18 ft\n"
]
}
],
"prompt_number": 12
}
],
"metadata": {}
}
]
}
|
