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{
"metadata": {
"name": "",
"signature": "sha256:47f72be1b9c6cd56213869831cb1984e5af98a10c08e54d4fdad5c35b07de8a5"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 11 : Introduction to Working of IC Engines"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 11.1 Page No : 264"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\n",
"# Variables\n",
"n = 3;\n",
"l = 80;\t\t\t# in mm\n",
"d = 76;\t\t\t# in mm\n",
"r = 8.5;\n",
"\n",
"# Calculations and Results\n",
"V_s = (math.pi/4.) * d * d * l;\t\t\t# in mm**3\n",
"V_s = V_s * 10**-3;\t\t\t# in cm**3\n",
"# r = 1+ (V_s/V_c)\n",
"V_c = (1/(r - 1)) * V_s;\t\t\t# in cm**3\n",
"print \"volume of cylinder in mm**3 is : \",round(V_c*10**3) #incorrect answer in the textbook\n",
"\n",
"C = V_s * n;\t\t\t# C s math.radians(numpy.tan(s for capacity of engine in cm**3\n",
"C = C * 10**-3;\t\t\t# in litre\n",
"print \"Capacity of the engine in litre is : %.3f\"%C\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"volume of cylinder in mm**3 is : 48389.0\n",
"Capacity of the engine in litre is : 1.089\n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}
|
