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{
"metadata": {
"name": "",
"signature": "sha256:11cb16e5df43b71fcfcbd028a413a4b4822b665e44e65d30bde344b1e73319cb"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 13 :\n",
"Thermodynamics of irreversible\n",
"processes"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 13.1 pg : 377"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\t\t\t\n",
"# Variables\n",
"Eab1 = 0.\n",
"Eab2 = 5.87 \t\t\t#mV\n",
"T1 = 150. \t\t\t#F\n",
"T2 = 200. \t \t\t#F\n",
"\t\t\t\n",
"# Calculations\n",
"Eab = -1.12+ 0.035*T1\n",
"pi1 = 0.035*(T1+460)\n",
"pi2 = 0.035*(T2+460)\n",
"\t\t\t\n",
"# Results\n",
"print \"Thermocouple reading at %d F = %.2f mv\"%(T1,Eab)\n",
"print \" Peltier coefficient at %d F = %.1f mv\"%(T1,pi1)\n",
"print \" Peltier coefficient at %d F = %.1f mv\"%(T2,pi2)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Thermocouple reading at 150 F = 4.13 mv\n",
" Peltier coefficient at 150 F = 21.4 mv\n",
" Peltier coefficient at 200 F = 23.1 mv\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 13.2 pg : 380"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\t\t\t\n",
"# Variables\n",
"T = 0. \t\t\t#C\n",
"\t\t\t\n",
"# Calculations\n",
"de1 = -72. \t\t\t#mV/C\n",
"de2 = 500. \t\t\t#mv/C\n",
"alpha = de1-de2\n",
"pi = -(T+273)*alpha\n",
"\t\t\t\n",
"# Results\n",
"print \"Peltier coefficient at %d C = %d mv\"%(T,pi/1000)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Peltier coefficient at 0 C = 156 mv\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
