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{
"metadata": {
"name": "",
"signature": "sha256:918b48292f00614bbba5ee6b8d2f7b2b929a3939332547fe2fb6585d1e0c7729"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 2:THERMODYNAMIC CONCEPTS AND THE ZEROTH LAW"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.1, Page No:33"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"patm = 14.5 ; # atmospheric pressure in psia\n",
"pgauge = 2.5; # gauge pressure in psia\n",
"A = 10; # Area of the piston in in^2\n",
"g=9.80665; # Acceleration due to gravity in m/s^2\n",
"#Calculation for (a)\n",
"p = patm + pgauge; #total pressure of gas\n",
"m=(p-patm)*A ; # mass of the piston\n",
"#Result for (a)\n",
"print \"In English units\"\n",
"print \"Mass of the piston =\",m,\"lbm\"\n",
"#Calculation for (b)\n",
"p=(p*0.454*g)/(0.0254**2); # conversion of English unit to SI units\n",
"patm=(patm*0.454*g)/(0.0254**2); # conversion of English unit to SI units\n",
"m = ((p-patm)*(A*2.54**2*10**-4))/g; # Mass of the piston\n",
"#Result for (b)\n",
"print \"\\nIn SI units \\n\",\"Mass of the piston =\",m,\"kg\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"In English units\n",
"Mass of the piston = 25.0 lbm\n",
"\n",
"In SI units \n",
"Mass of the piston = 11.35 kg\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.2, Page No:34"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#Variable declaration\n",
"d_r = 13600; # Density of manometric fluid (mercury) in kg/m^*3\n",
"g = 8.92; # Gravitational acceleration in m/s^2\n",
"#Variable declaration\n",
"z1=0.589*math.sin(math.radians(60)); # vertical height of fluid at section 1\n",
"z2=2*math.sin(math.radians(30)); # vertical height of fluid at section 2\n",
"z=z2-z1; # Difference in vertical heights of fluid\n",
"patm = 14.7; # Atmospheric pressure in lbf/in^2\n",
"patm=(patm*4.44822*144/0.3048**2); # conversion of lbf/in^2 unit to N/m^2 unit\n",
"p=patm + (d_r*g*(z2-z1)); # Balance of force at A\n",
"#Result\n",
"print \"Difference in vertical heights of fluid = \",round(z,2),\"m\"\n",
"print \"\\nThe pressure of fluid in the vessel = \",round(p/1000,0),\"kPa\" \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Difference in vertical heights of fluid = 0.49 m\n",
"\n",
"The pressure of fluid in the vessel = 161.0 kPa\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
