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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 4:Defining Thermodynamic State:The State Postulate"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4.1,Page no:51"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 4.1\n",
"\n",
"#to find the mass of substance present in liquid and vapour phase \n",
"#Variable declaration\n",
"M=2.5 \t\t\t\t#mass of the substance[Kg]\n",
"x=0.6 \t\t\t\t#mass fraction for vapour phase \n",
"P=7 \t\t\t\t#pressure [atm]\n",
"T=438 \t\t\t\t#temperature[K]\n",
"\n",
"#Calculation\n",
"Ml=(1-x)*M \t\t\t#mass fraction of liquid phase[Kg]\n",
"Mg=x*M \t\t\t\t#mass fraction of vapour phase[Kg]\n",
"#Result\n",
"print\"M(liquid phase)=\",Ml,\"Kg\\nM(vapour phase)=\",Mg,\"Kg\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"M(liquid phase)= 1.0 Kg\n",
"M(vapour phase)= 1.5 Kg\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4.2,Page no:51"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 4.2\n",
"\n",
"#to find the total volume occupied by the mixture \n",
"#Variable declaration\n",
"Vl=0.0177 \t\t\t#specific volume of saturated liquid[m3/Kg]\n",
"Vg=4.43 \t\t\t#specific volume of saturated vapour[m3/Kg]\n",
"P=7 \t\t\t\t#pressure[atm]\n",
"T=438 \t\t\t\t#temperature[K]\n",
"x=0.6 \t\t\t\t#fraction of vapour phase\n",
"M=2.5 \t\t\t\t#mass of the substance[Kg]\n",
"\n",
"#Calculation\n",
"V=((1-x)*Vl+x*Vg)*M \t\t#total volume occupied [m3]\n",
"#result\n",
"print\"Total volume occupied =\",round(V,2),\"m^3\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Total volume occupied = 6.66 m^3\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4.3,Page no:51"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 4.3\n",
"\n",
"#to find the total internal energy of the mixture\n",
"#Variable declaration\n",
"M=2.5 \t\t\t\t#mass of a substance[Kg]\n",
"x=0.6 \t\t\t\t#fraction of vapour phase \n",
"Ug=1105.0 \t\t\t#specific internal energy of saturated vapour[J/Kg]\n",
"Ul=298.0 \t\t\t\t#specific internal energy of saturated liquid[J/Kg] \n",
"#Calculation\n",
"U=M*((1-x)*Ul+x*Ug) \n",
"#Result\n",
"print\"The total internal energy of the mixture =\",U,\"J\"\n",
"print\"\\nNOTE:In textbook,it is wrongly calculated as 1950 J\"\n",
" "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The total internal energy of the mixture = 1955.5 J\n",
"\n",
"NOTE:In textbook,it is wrongly calculated as 1950 J\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|
