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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 2:Important terminologies in Thermodynamics "
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.1,Page no:13"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 2.1\n",
"#Find out molar constant pressure heat capacity\n",
"#Variable Declaration\n",
"m=25.0 \t\t\t\t#weight of water vapour [grams]\n",
"w=18.0 \t\t\t\t#molecular weight of water vapour [grams/mol]\n",
"T=9.69 \t\t\t\t#increase in temperature [K]\n",
"Qp=0.45 \t\t\t#heat supplied at constant pressure[KJ]\n",
"#To find the molar constant pressure specific heat\n",
"\n",
"#Calculation\n",
"n=m/w \t\t\t\t#no. of moles of water vapour\n",
"Cp=Qp/(n*T) \t\t\t#specific heat capacity at constant pressure[KJ]\n",
"Cp=Cp*1000\t\t\t#specific heat capacity at constant pressure[J]\n",
"\n",
"#Result\n",
"print\"The specific heat capacity at constant pressure =\",round(Cp,2),\"J K^-1 mol^-1\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The specific heat capacity at constant pressure = 33.44 J K^-1 mol^-1\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.2,Page no:14"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 2.2\n",
"#To find the minimum work of compression \n",
"import math\n",
"#Variable declaration\n",
"m=16.0 \t\t\t\t#weight of oxygen [grams]\n",
"w=32.0 \t\t\t\t#molecular weight of oxygen [grams/mol]\n",
"T=300.0 \t\t\t\t#Temperature during compression [K]\n",
"P1=1.0 \t\t\t\t#initial pressure of process [atm]\n",
"P2=100.0 \t\t\t\t#final pressure of process[atm]\n",
"R=8.314 \t\t\t#Universal gas constant [J/K/mol]\n",
"#Calculation\t\n",
"n=m/w \t\t\t\t#no. of moles of oxygen\n",
"W=-n*R*T*math.log(P1/P2) \n",
"#Result\n",
"print\"Mininmum work done to compress oxygen =\",round(W),\"J(approx)\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Mininmum work done to compress oxygen = 5743.0 J(approx)\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
