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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# 1: Bonding in Solids"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example number 1, Page number 1.21"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"-2*a/r**3 + 90*b/r**11\n"
]
}
],
"source": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"from sympy import diff,Symbol\n",
"import numpy as np\n",
"\n",
"#Variable declaration\n",
"n=1;\n",
"m=9;\n",
"a=Symbol('a')\n",
"b=Symbol('b')\n",
"r=Symbol('r')\n",
"\n",
"#Calculation\n",
"y=(-a/(r**n))+(b/(r**m));\n",
"y=diff(y,r);\n",
"y=diff(y,r);\n",
"\n",
"#Result\n",
"print y"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"young's modulus is 157 GPa\n"
]
}
],
"source": [
"#since the values of a,b,r are declared as symbols in the above cell, it cannot be solved there. hence it is being solved here with the given variable declaration\n",
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"a=7.68*10**-29; \n",
"r0=2.5*10**-10; #radius(m)\n",
"\n",
"#Calculation\n",
"b=a*(r0**8)/9;\n",
"y=((-2*a*r0**8)+(90*b))/r0**11; \n",
"E=y/r0; #young's modulus(Pa)\n",
"\n",
"#Result\n",
"print \"young's modulus is\",int(E/10**9),\"GPa\""
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example number 2, Page number 1.22"
]
},
{
"cell_type": "code",
"execution_count": 7,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"effective charge is 0.72 *10**-19 coulomb\n",
"answer given in the book is wrong\n"
]
}
],
"source": [
"#importing modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"dm=1.98*10**-29/3; #dipole moment\n",
"l=0.92*10**-10; #bond length(m)\n",
"\n",
"#Calculation\n",
"ec=dm/l; #effective charge(coulomb)\n",
"\n",
"#Result\n",
"print \"effective charge is\",round(ec*10**19,2),\"*10**-19 coulomb\"\n",
"print \"answer given in the book is wrong\""
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 2",
"language": "python",
"name": "python2"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 2
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython2",
"version": "2.7.11"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|
