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|
{
"metadata": {
"name": "",
"signature": "sha256:a712c503532bf01630566d0248f8b9fe4ae07a136310d2bc72cf3a40e429d9f4"
},
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 6: Semiconductor Physics"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.1,Page number 190"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"S = [[1,2],[3,4],[5,6],[7,8]]; # Declare a 4X2 matrix\n",
"# Enter material names\n",
"S[0][0] = 'Si'; S[1][0] = 'GaAs'; S[2][0] = 'GaP'; S[3][0] = 'ZnS';\n",
"# Enter energy band gap values\n",
"S[0][1] = 1.11; S[1][1] = 1.42; S[2][1] = 2.26; S[3][1] = 3.60;\n",
"h = 6.626*10**-34; # Planck's constant, Js\n",
"c = 3*10**8; # Speed of light, m/s\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"print\"______________________________________________________\";\n",
"print\"Material E_g (eV) Critical Wavelength (micron)\";\n",
"print\"______________________________________________________\";\n",
"for i in range (0,4) :\n",
" lamda = h*c/(S[i][1]*e);\n",
" print\"\", S[i][0],\" \", S[i][1],\" \",round(lamda/10**-6,3);\n",
"\n",
"print\"______________________________________________________\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"______________________________________________________\n",
"Material E_g (eV) Critical Wavelength (micron)\n",
"______________________________________________________\n",
" Si 1.11 1.119\n",
" GaAs 1.42 0.875\n",
" GaP 2.26 0.55\n",
" ZnS 3.6 0.345\n",
"______________________________________________________\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.2,Page number 192"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"c = 3*10**8; # Speed of light, m/s\n",
"h = 6.626*10**-34; # Planck's constant, Js\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"omega = 2e+014; # Wave vector involved in phonon energy, rad per sec\n",
"f = omega/(2*pi); # Frequency of the wave, Hz \n",
"E = h*f/e; # Phonon energy involved in Si to lift the electron, eV\n",
"print\"The phonon energy involved in Si =\",round(E,4),\"eV which is insufficient to lift an electron.\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The phonon energy involved in Si = 0.1318 eV which is insufficient to lift an electron.\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.3,Page number 192"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"N_A = 6.023*10**23; # Avogadro's number\n",
"# For Si\n",
"A = 28.1; # Atomic weight of Si, g/mol\n",
"a = 5.43*10**-8; # Lattice constant for Si, cm\n",
"n = 8.0/a**3; # Number of atoms per unit volume, atoms/cc\n",
"rho = n*A/N_A; # Density of Si, g/cc\n",
"print\"The density of Si =\",round(rho,3),\"atoms per cc\";\n",
"# For GaAs\n",
"A = 69.7+74.9; # Atomic weight of GaAs, g/mol\n",
"a = 5.65*10**-8; # Lattice constant for Si, cm\n",
"n = 4.0/a**3; # Number of atoms per unit volume, atoms/cc\n",
"rho = n*A/N_A; # Density of GaAs, g/cc\n",
"print\"The density of GaAs =\",round(rho,3),\"toms per cc\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The density of Si = 2.331 atoms per cc\n",
"The density of GaAs = 5.324 toms per cc\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.4,Page number 196"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"m = 9.11*10**-31; # Electron Rest Mass , kg\n",
"k = 1.38*10**-23; # Boltzmann constant, J/mol/K\n",
"h = 6.626*10**-34; # Planck's constant, Js\n",
"T = 300.0; # Room temperature, K\n",
"m_e = 0.068*m; # Mass of electron, kg\n",
"m_h = 0.56*m; # Mass of hole, kg\n",
"E_g = 1.42*1.6*10**-19; # Energy band gap for GaAs, J\n",
"n_i = 2*(2*pi*k*T/h**2)**(3.0/2)*(m_e*m_h)**(3.0/4)*exp(-E_g/(2*k*T));\n",
"print\"The Intrinsic carrier concentration of GaAs at 300 K =\",\"{0:.3e}\".format(n_i),\"per metre cube\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The Intrinsic carrier concentration of GaAs at 300 K = 2.618e+12 per metre cube\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.5,Page number 197"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"m = 9.11*10**-31; # Electron Rest Mass , kg\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"k = 1.38*10**-23; # Boltzmann constant, J/mol/K\n",
"T = 300.0; # Room temperature, K\n",
"m_e = 1.1*m; # Mass of electron, kg\n",
"m_h = 0.56*m; # Mass of hole, kg\n",
"E_g = 1.1; # Energy band gap for GaAs, J\n",
"E_F = E_g/2+3.0/4*k*T/e*log(m_h/m_e); # Position of Fermi level of Si at room temperature, eV\n",
"print\"The position of Fermi level of Si at room temperature =\",round(E_F,3),\"eV\";\n",
"print\"The fermi level in this case is shifted downward from the midpoint (0.55 eV) in the forbiddem gap.\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The position of Fermi level of Si at room temperature = 0.537 eV\n",
"The fermi level in this case is shifted downward from the midpoint (0.55 eV) in the forbiddem gap.\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.6,Page number 197"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"e = 1.6*10**-19; # Electronic charge, C\n",
"n_i = 2.15*10**13; # Carrier density of Ge at room temperature, per cc\n",
"mu_e = 3900.0; # Mobility of electron, cm-square/V-s\n",
"mu_h = 1900.0; # Mobility of hole, cm-square/V-s\n",
"sigma_i = e*(mu_e+mu_h)*n_i; # Intrinsic conductivity of Ge, mho per m\n",
"rho_i = 1.0/sigma_i; # Intrinsic resistivity of Ge at room temperature, ohm-m\n",
"print\"The intrinsic resistivity of Ge at room temperature =\",round(rho_i,2),\"ohm-cm\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The intrinsic resistivity of Ge at room temperature = 50.12 ohm-cm\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.7,Page number 197"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"m = 9.1*10**-31; # Mass of an electron, kg\n",
"e = 1.6*10**-19; # Electronic charge, C\n",
"k = 1.38*10**-23; # Boltzmann constant, J/mol/K\n",
"T = 30.0; # Given temperature, K\n",
"n = 10**22; # Carrier density of CdS, per metre cube\n",
"mu = 10**-2; # Mobility of electron, metre-square/V-s\n",
"sigma = e*mu*n; # Conductivity of CdS, mho per m\n",
"print\"The conductivity of CdS sample =\",round(sigma,2),\"mho per m\";\n",
"m_eff = 0.1*m; # Effective mass of the charge carries, kg\n",
"t = m_eff*sigma/(n*e**2); # Average time between successive collisions, s\n",
"print\"The average time between successive collisions =\",\"{0:.3e}\".format(t),\"sec\";\n",
"# We have 1/2*m_eff*v**2 = 3/2*k*T, solving for v\n",
"v = sqrt(3*k*T/m_eff); # Velocity of charrge carriers, m/s\n",
"l = v*t; # Mean free distance travelled by the carrier, m\n",
"print\"The mean free distance travelled by the carrier =\",\"{0:.3e}\".format(l),\"m\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The conductivity of CdS sample = 16.0 mho per m\n",
"The average time between successive collisions = 5.688e-15 sec\n",
"The mean free distance travelled by the carrier = 6.644e-10 m\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.8,Page number 199"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"k = 1.38*10**-23; # Boltzmann constant, J/mol/K\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"T = [385.0, 455.0, 556.0, 714.0]; # Temperatures of Ge, K\n",
"rho = [0.028, 0.0061, 0.0013, 0.000274]; # Electrical resistivity, ohm-m\n",
"Tinv = [0.0, 0.0, 0.0, 0.0]; # Create an empty row matrix for 1/T\n",
"ln_sigma = [0.0, 0.0, 0.0, 0.0]; # Create the empty row matrix for log(sigma)\n",
"for i in xrange(len(T)):\n",
" Tinv[i] = 1/T[i];\n",
" ln_sigma[i] = log(1.0/rho[i]);\n",
"# Plot the graph\n",
"plot(Tinv, ln_sigma);\n",
"axis([0,0.003,0,9])\n",
"title('Plot of ln (sigma) vs 1/T');\n",
"xlabel('1/T');\n",
"ylabel('ln (sigma)');\n",
"show();\n",
"\n",
"\n",
"# Calculate slope\n",
"slope = (ln_sigma[2]-ln_sigma[1])/(Tinv[2]-Tinv[1]);\n",
"E_g = abs(2*slope*k); # Energy gap of Ge, J\n",
"print\"The energy gap of Ge =\",E_g/e,\"eV\";\n",
"\n",
"# Result \n",
"# The energy gap of Ge = 0.658 eV "
],
"language": "python",
"metadata": {},
"outputs": [
{
"metadata": {},
"output_type": "display_data",
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2lYWFBX788Ufk5+dj/PjxOHPmDPz8/PTv3z3uoNVqodVq5U6JiMik6HQ66HQ6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\nGIiISOL/AVf2bVIyj9ReAAAAAElFTkSuQmCC\n",
"text": [
"<matplotlib.figure.Figure at 0x7fe3a9ddb6d0>"
]
},
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The energy gap of Ge = 0.667947295491 eV\n"
]
}
],
"prompt_number": 27
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.9,Page number 199"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"h = 6.626*10**-34; # Planck's constant, Js\n",
"c = 3*10**8; # Speed of light, m/s\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"x = 0.07; # Al concentration in host GaAs\n",
"E_g = 1.424 + 1.266*x + 0.266*x**2; # Band gap of GaAs as a function of x, eV\n",
"# As E_g = h*c/lambda, solving for lambda\n",
"lamda = h*c/(E_g*e); # Emission wavelength of light, m\n",
"print\"The energy band gap of Al doped GaAs =\",round(E_g,3),\"eV\";\n",
"print\"The emission wavelength of light =\",round(lamda*10**6,3),\"micron\";\n",
"print\"The Al atoms go as substitutional impurity in the host material.\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The energy band gap of Al doped GaAs = 1.514 eV\n",
"The emission wavelength of light = 0.821 micron\n",
"The Al atoms go as substitutional impurity in the host material.\n"
]
}
],
"prompt_number": 30
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.10,Page number 200"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"x = 0.38; # Al concentration in host GaAs\n",
"E_g = 1.424 + 1.266*x + 0.266*x**2; # Band gap of GaAs as a function of x, eV\n",
"print\"The energy band gap of 38 percent Al doped in GaAs =\",round(E_g,3),\"eV\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The energy band gap of 38 percent Al doped in GaAs = 1.943 eV\n"
]
}
],
"prompt_number": 32
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.11,Page number 200"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"k = 1.38*10**-23; # Boltzmann constant, J/mol/K\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"rho_40 = 0.2; # Resistivity of Ge at 40 degree celsius, ohm-m\n",
"T1 = 40+273; # Temperature at which resistivity of Ge becomes 0.2 ohm-m, K\n",
"T2 = 20+273; # Temperature at which resistivity of Ge is to be calculated, K\n",
"E_g = 0.7; # Band gap of Ge, eV\n",
"# As rho = exp(E_g/(2*k*T)), so for rho_20\n",
"rho_20 = rho_40*exp(E_g/(2*k/e)*(1.0/T2-1.0/T1)); # Resistivity of Ge at 20 degree celsius, ohm-m\n",
"print\"The resistivity of Ge at 20 degree celsius =\",round(rho_20,1),\"ohm-m\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The resistivity of Ge at 20 degree celsius = 0.5 ohm-m\n"
]
}
],
"prompt_number": 35
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.12,Page number 203"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"k = 1.38*10**-23; # Boltzmann constant, J/mol/K\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"T = 300.0; # Room temperature of the material, K\n",
"K_Si = 11.7; # Dielectric constant of Si\n",
"K_Ge = 15.8; # Dielectric constant of Ge\n",
"m = 9.1*10**-31; # Mass of an electron, kg\n",
"m_eff = 0.2; # Effective masses of the electron in both Si and Ge, kg\n",
"E_ion_Si = 13.6*m_eff/K_Si**2; # Donor ionization energy of Si, eV\n",
"E_ion_Ge = 13.6*m_eff/K_Ge**2; # Donor ionization energy of Ge, eV\n",
"E = k*T/e; # Energy available for electrons at 300 K, eV\n",
"print\"The donor ionization energy of Si =\",round(E_ion_Si,4),\"eV\";\n",
"print\"The donor ionization energy of Ge =\",round(E_ion_Ge,4),\"eV\";\n",
"print\"The energy available for electrons at 300 K =\",round(E,4),\"eV\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The donor ionization energy of Si = 0.0199 eV\n",
"The donor ionization energy of Ge = 0.0109 eV\n",
"The energy available for electrons at 300 K = 0.0259 eV\n"
]
}
],
"prompt_number": 38
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.13,Page number 203"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"epsilon = 15.8; # Dielectric constant of Ge \n",
"m = 9.1*10**-31; # Mass of an electron, kg\n",
"m_e = 0.2*m; # Effective masses of the electron in Ge, kg\n",
"a_Ge = 5.65; # Lattice parameter of Ge, angstrom\n",
"A_d = 0.53*epsilon*(m/m_e); # Radius of donor atom, angstrom\n",
"print\"The radius of the orbits of fifth valence electron of acceptor impurity =\",ceil(A_d),\"angstrom\";\n",
"print\"This radius is\",ceil(A_d/a_Ge),\"times the lattice constant of Ge\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The radius of the orbits of fifth valence electron of acceptor impurity = 42.0 angstrom\n",
"This radius is 8.0 times the lattice constant of Ge\n"
]
}
],
"prompt_number": 43
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.14,Page number 203"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"e = 1.6*10**-19; # Energy equivalent of 1 eV, J/eV\n",
"tau = 10**-12; # Life time of electron in Ge, s\n",
"m = 9.1*10**-31; # Mass of an electron, kg\n",
"m_e = 0.5*m; # Effective masses of the electron in Ge, kg\n",
"mu = e*tau/m_e; # Mobility of electron in Ge, m-square/V-s\n",
"n_i = 2.5*10**19; # Intrinsic carrier concentration of Ge at room temperature, per metre cube\n",
"n_Ge = 5*10**28; # Concentration of Ge atoms, per metre cube\n",
"n_e = n_Ge/10**6; # Concentration of impurity atoms, per metre cube\n",
"# From law of mass action, n_e*n_h = n_i**2, solving for n_h\n",
"n_h = n_i**2/n_e; # Concentration of holes, per metre cube\n",
"\n",
"print\"This mobility of electron in Ge =\",round(mu/10**-4,1),\"cm-square/V-s\";\n",
"print\"This concentration of holes in Ge =\",\"{0:.3e}\".format(n_h),\"per metre cube\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"This mobility of electron in Ge = 3516.5 cm-square/V-s\n",
"This concentration of holes in Ge = 1.250e+16 per metre cube\n"
]
}
],
"prompt_number": 48
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.15,Page number 204"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"n_i = 2.5*10**19; # Intrinsic carrier concentration of Ge at room temperature, per metre cube\n",
"n_Ge = 5*10**28; # Concentration of Ge atoms, per metre cube\n",
"delta_d = 10**6; # Rate at which pentavalent impurity is doped in pure Ge, ppm\n",
"n_e = n_Ge/delta_d; # Concentration of impurity atoms, per metre cube\n",
"# From law of mass action, n_e*n_h = n_i**2, solving for n_h\n",
"n_h = n_i**2/n_e; # Concentration of holes, per metre cube\n",
"\n",
"print\"This concentration of holes in Ge =\",\"{0:.3e}\".format(n_h),\"per metre cube\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"This concentration of holes in Ge = 1.250e+16 per metre cube\n"
]
}
],
"prompt_number": 51
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.16,Page number 205"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#Given Data\n",
"e = 1.6*10**-19; # Charge on an electron, C\n",
"mu = 1400*10**-4; # Mobility of electron, metre-square per volt per sec\n",
"l = 300-6; # Length of the n-type semiconductor, m\n",
"w = 100-6; # Width of the n-type semiconductor, m\n",
"t = 20-6; # Thickness of the n-type semiconductor, m\n",
"N_D = 4.5*10**21; # Doping concentration of donor impurities, per metre-cube\n",
"V = 10; # Biasing voltage for semiconductor, V\n",
"B_prep = 1; # Perpendicular magnetic field to which the semiconductor is subjected, tesla\n",
"\n",
"# Part (a)\n",
"n = N_D; # Electron concentration in semiconductor, per cc\n",
"R_H = -1.0/(n*e); # Hall Co-efficient, per C per metre cube\n",
"\n",
"# Part (b)\n",
"rho = 1.0/(n*e*mu); # Resistivity of semiconductor, ohm-m\n",
"R = rho*l/(w*t); # Resistance of the semiconductor, ohm\n",
"I = V/R; # Current through the semiconductor, A\n",
"V_H = R_H*I*B_prep/t; # Hall voltage, V\n",
"\n",
"# Part (c)\n",
"theta_H = math.degrees(math.atan(-mu*B_prep)); # Hall angle, degrees\n",
"\n",
"\n",
"print\"Hall coefficient, R_H =\",\"{0:.3e}\".format(R_H),\"per C metre cube\";\n",
"print\"Hall voltage, V_H = \",math.fabs(V_H),\"V\";\n",
"print\"Hall angle, theta_H =\",round(theta_H,3),\"degree\";\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Hall coefficient, R_H = -1.389e-03 per C metre cube\n",
"Hall voltage, V_H = 0.447619047619 V\n",
"Hall angle, theta_H = -7.97 degree\n"
]
}
],
"prompt_number": 60
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|