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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 5 : Power Amplifiers"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.1, Page No. 167"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# efficiency\n",
"\n",
"import math\n",
"#Variable declaration\n",
"Pac=0.1 #in W\n",
"Vcc=20.0 #in V\n",
"Ic=20.0 #in mA\n",
"\n",
"#Calculations\n",
"Pdc=Vcc*Ic*10**-3 #in W\n",
"eta=(Pac/Pdc)*100 #efficiency\n",
"\n",
"#Result\n",
"print(\"efficiency is ,(%%)= %.f\"%eta)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"efficiency is ,(%)= 25\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.2, Page No. 167"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# collector current\n",
"\n",
"import math\n",
"#Variable declaration\n",
"Pac=2.0 #in W\n",
"Vcc=12.0 #in V\n",
"\n",
"#Calculations\n",
"Ic=(Pac*math.sqrt(2)*math.sqrt(2))/Vcc\n",
"\n",
"#Result\n",
"print(\"maximum collector current is ,(A)= %.2f\" %Ic)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"maximum collector current is ,(A)= 0.33\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.3, Page No. 167"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# collector efficiency and power rating\n",
"\n",
"import math\n",
"#Variable declaration\n",
"Pac=3.0 #in W\n",
"Pdc=10.0 #in W\n",
"\n",
"#Calculations\n",
"eta=(Pac/Pdc)*100 #percentage efficieny \n",
"\n",
"#Result\n",
"print(\"collector efficiency is , (%%) = %.f\"%eta)\n",
"print(\"power rating of transistor is ,(W) = %.f\" %Pdc)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"collector efficiency is , (%) = 30\n",
"power rating of transistor is ,(W) = 10\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.4, Page No. 168"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# power\n",
"\n",
"import math\n",
"#Variable declaration\n",
"dIc=100.0 #in mA\n",
"Rl=6.0 #in ohm\n",
"Rl=6.0 #in ohm\n",
"dVc=10.0 #in V\n",
"\n",
"#Calculations\n",
"mv=dIc*Rl*10**-3 #in V\n",
"pd=mv*dIc #in mW\n",
"oi=(dVc/dIc)*10**3 #in ohm\n",
"n=math.sqrt(oi/Rl) #turn ratio of transformer\n",
"tsv=dVc/n #om V\n",
"Il=tsv/Rl #in A\n",
"ptr= Il**2*Rl*10**3 #in mW\n",
"\n",
"#Result\n",
"print(\"(i) power developed in loudspeaker is , (mW)= %.f\"%pd)\n",
"print(\"(ii) power transferred to loudspeaker is ,(mw)= %.f\"%ptr)\n",
"#in textbook in second case there is one point deviation in the answer."
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(i) power developed in loudspeaker is , (mW)= 60\n",
"(ii) power transferred to loudspeaker is ,(mw)= 1000\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.5, Page No. 168"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# power\n",
"\n",
"import math\n",
"#Variable declaration\n",
"n=10.0 #turn ratio\n",
"Rl=10.0 #ohm\n",
"Ic=100.0 #in mA\n",
"\n",
"#Result\n",
"Rld=n**2*Rl #in ohm\n",
"Irms=Ic/(math.sqrt(2)) #in mA\n",
"P=Irms**2*Rld #in W\n",
"\n",
"#Result\n",
"print(\"maximum power output is ,(W)= %.f\"%(P*10**-6))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"maximum power output is ,(W)= 5\n"
]
}
],
"prompt_number": 20
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.6, Page No. 169"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# harmonic distortions and change in power\n",
"\n",
"import math\n",
"#Variable declaration\n",
"#ie=15*sin 400*t+1.5*sin 800*t + 1.2*sin 1200*t + 0.5*sin 1600*t given equation\n",
"I2=1.5 #in A\n",
"I1=15.0 #in A\n",
"I3=1.2 #in A\n",
"I4=0.5 #in A\n",
"D2=(I2/I1)*100 #Second percentage harmonic distortion\n",
"D3=(I3/I1)*100 #Third percentage harmonic distortion\n",
"#in book I2 is mentioned wrongly in place of I1\n",
"D4=(I4/I1)*100 #Fourth percentage harmonic distortion\n",
"D=math.sqrt(D2**2+D3**2+D4**2)/100 #Distortion Factor\n",
"P1=1.0 #assume\n",
"P=(1+D**2)*P1 #in W\n",
"peri=((P-P1)/P1)*100 #percentage increase in power due to distortion\n",
"\n",
"#Result\n",
"print(\"part (i)\")\n",
"print(\"Second percentage harmonic distortion (D2) is ,(%%) = %.f\"%D2)\n",
"print(\"Third percentage harmonic distortion (D3) is ,(%%) = %.f\"%D3)\n",
"print(\"Fourth percentage harmonic distortion (D4) is ,(%%) = %.2f\"%D4)\n",
"print(\"\\npart (ii)\")\n",
"print(\"percentage increase in power due to distortion is ,(%%) = %.2f\"%peri)\n",
"# answer for % increase is slightly different than book"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"part (i)\n",
"Second percentage harmonic distortion (D2) is ,(%) = 10\n",
"Third percentage harmonic distortion (D3) is ,(%) = 8\n",
"Fourth percentage harmonic distortion (D4) is ,(%) = 3.33\n",
"\n",
"part (ii)\n",
"percentage increase in power due to distortion is ,(%) = 1.75\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.7, Page No. 169"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# power dissipated\n",
"\n",
"import math\n",
"#Variable declaration\n",
"Vcc=15.0 #in V\n",
"Vpeak=24.0/2 #in V\n",
"Rl=100.0 #in ohm\n",
"\n",
"#Calculations\n",
"Ipeak= Vpeak/Rl #in A\n",
"Pdc=Vcc*(2/(math.pi))*Ipeak #in W\n",
"pad=(1.0/2)*(Vpeak**2)/Rl #in W\n",
"pd=Pdc-pad #in W\n",
"pde=pd/2 #in W\n",
"\n",
"#Result\n",
"print(\"power dissipated by each transistor is,(mW)= %.f\"%(pde*10**3))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"power dissipated by each transistor is,(mW)= 213\n"
]
}
],
"prompt_number": 28
}
],
"metadata": {}
}
]
}
|
