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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 2 Rectifier Diodes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.1 Page No 29"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The output voltage = 15.00 volts\n",
"The current = 1.50 mA\n"
]
}
],
"source": [
"# given data\n",
"Vin= 15.0## V\n",
"R_L= 10.0## kΩ\n",
"# The output voltage\n",
"Vout= Vin ## V\n",
"# The current\n",
"I= Vout/R_L## mA\n",
"print \"The output voltage = %.2f volts\"%Vout\n",
"print \"The current = %.2f mA\"%I"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.2 Page No 30"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The output voltage = 0 volts\n",
"The voltage across the diode = 15.00 volts\n"
]
}
],
"source": [
"# given data\n",
"Vin= 15.0## V\n",
"I=0#\n",
"R_L= 10.0## kΩ\n",
"R_L= R_L*10**3## Ω\n",
"# The output voltage \n",
"Vout= I*R_L## V\n",
"# The voltage across the diode \n",
"V_R= Vin-Vout## V\n",
"print \"The output voltage = %.f volts\"%Vout\n",
"print \"The voltage across the diode = %.2f volts\"%V_R"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.4 Page No 31"
]
},
{
"cell_type": "code",
"execution_count": 9,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The peak current through the diode = 1.50 mA\n",
"The maximum reverse voltage = 15.00 volts\n"
]
}
],
"source": [
"# given data\n",
"Vin= 15.0## V\n",
"V_P= Vin## V\n",
"R_L= 10## kΩ\n",
"R_L= R_L*10**3## Ω\n",
"Vout=0#\n",
"# The peak current through the diode \n",
"I_P= V_P/R_L## A\n",
"# The maximum reverse voltage \n",
"V_R= Vin-Vout## V\n",
"I_P= I_P*10**3## mA\n",
"print \"The peak current through the diode = %.2f mA\"%I_P\n",
"print \"The maximum reverse voltage = %.2f volts\"%V_R"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.5 Page No 33"
]
},
{
"cell_type": "code",
"execution_count": 10,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The output voltage = 14.30 volts\n",
"The current = 1.43 mA\n",
"The power dissipation of the diode = 1.00 mW\n"
]
}
],
"source": [
"# given data\n",
"Vin= 15.0## V\n",
"V_K= 0.7## V\n",
"R_L= 10.0## kΩ\n",
"R_L= R_L*10**3## Ω\n",
"# The output voltage \n",
"Vout= Vin-V_K## V\n",
"# The current \n",
"I= Vout/R_L## A\n",
"# The power dissipation of the diode \n",
"P= V_K*I## W\n",
"I=I*10**3## mA\n",
"P= round(P*10**3)## mW\n",
"print \"The output voltage = %.2f volts\"%Vout\n",
"print \"The current = %.2f mA\"%I\n",
"print \"The power dissipation of the diode = %.2f mW\"%P"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.6 Page No 34"
]
},
{
"cell_type": "code",
"execution_count": 11,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The peak output voltage = 14.30 volts\n",
"The maximum forward current = 1.43 mA\n",
"The peak inverse voltage = 15.00 volts\n"
]
}
],
"source": [
"# given data\n",
"Vin= 15.0## V\n",
"V_K= 0.7## V\n",
"Vout=0## V\n",
"R_L= 10.0## kΩ\n",
"R_L= R_L*10**3## Ω\n",
"# The peak output voltage \n",
"V_P= Vin-V_K## V\n",
"# The maximum forward current \n",
"I_P= V_P/R_L## A\n",
"# The peak inverse voltage \n",
"PIV= Vin-Vout## V\n",
"I_P= I_P*10**3## mA\n",
"print \"The peak output voltage = %.2f volts\"%V_P\n",
"print \"The maximum forward current = %.2f mA\"%I_P\n",
"print \"The peak inverse voltage = %.2f volts\"%PIV"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.7 Page No 36"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The peak voltage = 9.12 volts\n",
"The peak inverse voltage = 10.00 volts\n"
]
}
],
"source": [
"# given data\n",
"Vin= 10.0## V\n",
"V_K= 0.7## V\n",
"Vout=0## V\n",
"R_L= 1000.0## kΩ\n",
"r_B= 20.0## Ω\n",
"# The peak forward current,\n",
"I_P= (Vin-V_K)/(R_L+r_B)## A\n",
"# The peak voltage \n",
"V_P= I_P*R_L## V\n",
"# The peak inverse voltage \n",
"PIV= Vin-Vout## V\n",
"print \"The peak voltage = %.2f volts\"%V_P\n",
"print \"The peak inverse voltage = %.2f volts\"%PIV"
]
}
],
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"kernelspec": {
"display_name": "Python 2",
"language": "python",
"name": "python2"
},
"language_info": {
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"file_extension": ".py",
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|
