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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 4: p-n Junction"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4.1, Page92"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"Na=10**18;#concentration\n",
"Nd=10**15;#concentration\n",
"N=9.65*10**9\n",
"\n",
"#calculation\n",
"Vb=.0259*log(Na*Nd/N**2);#built in potential\n",
"\n",
"#result\n",
"print\"built in potential is\",round(Vb,3),\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Populating the interactive namespace from numpy and matplotlib\n",
"built in potential is 0.777 V\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example4.2 Page96"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"Na=10**19;#concentration\n",
"Nd=10**16#concentration\n",
"N=9.65*10**9\n",
"q=1.6*10**-19#charge\n",
"Es=10**-12;#constant\n",
"\n",
"#calculation\n",
"Vb=.0259*log(Na*Nd/N**2);#voltage\n",
"W=(2*Es*Vb/q/Nd)**.5;#width\n",
"Em=q*W*Na/Es;#field\n",
"\n",
"#result\n",
"print\"built in potential is\",round(Vb,3),\"V\"\n",
"print\"depletion layer width is\",round(W*10**4,3),\"micro-m\"\n",
"print\"maximum field at zero bias is\",round(Em/10299,0),\"V/cm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"built in potential is 0.896 V\n",
"depletion layer width is 0.335 micro-m\n",
"maximum field at zero bias is 5200.0 V/cm\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example4.3 Page 99"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"I=10**20;#impurity\n",
"W=.50;#width\n",
"q=1.6*10**-19;#charge\n",
"E=8.85*10**-14#constant\n",
"N=9.65*10**9;#concentration\n",
"\n",
"#calculation\n",
"Em=q*I*W**2/(8*11.9*E);#maximum field\n",
"Vb=.0259*I*W/N/2;#built-in voltage\n",
"\n",
"#result\n",
"print\"maximum field is\",round(Em/10**8,0),\"V/cm\"\n",
"print\"built-in voltage is\",round(Vb/10**8,2),\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"maximum field is 4748.0 V/cm\n",
"built-in voltage is 0.67 V\n"
]
}
],
"prompt_number": 14
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example4.4 Page101"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"Na=2*10**19;#concentration\n",
"Nd=8*10**15;#concentration\n",
"V=4.0;#voltage\n",
"N=9.65*10**9\n",
"q=1.6*10**-19;#charge\n",
"E=10.53*10**-13#constant\n",
"\n",
"#calculation\n",
"Vb=.0259*log(Na*Nd/N**2);#voltage at zero bias\n",
"W1=(2*E*Vb/q/Nd)**.5;#width\n",
"C1=E/W1;#capacitance at zero bias\n",
"W2=(2*E*(Vb+V)/q/Nd)**.5;#width\n",
"C2=E/W2;#capacitance at reverse bias\n",
"\n",
"#result\n",
"print\"capacitance at zero bias is\",round(C1,11),\"F/cm^2\"\n",
"print\"capacitance at reverse bias is\",round(C2,11),\"F/cm^2\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"capacitance at zero bias is 2.723e-08 F/cm^2\n",
"capacitance at reverse bias is 1.172e-08 F/cm^2\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4.5 Page109"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"Na=5*10**16;#concentration\n",
"Nd=10**16;#concentration\n",
"N=9.65*10**9\n",
"Dn=21\n",
"A=2*10**-4;#area\n",
"Dp=10\n",
"T=5*10**-7;#time\n",
"q=1.6*10**-19;#charge\n",
"\n",
"#calculation\n",
"J=q*(N**2)*(((Dp/T)**.5)/Nd +((Dn/T)**.5)/Na);#current density\n",
"I=A*J;#ideal reverse current\n",
"\n",
"#result\n",
"print\"ideal reverse current is\",round(I,17),\"A\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"ideal reverse current is 1.72e-15 A\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example4.6 Page110"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"Na=5*10**16;#concentration\n",
"Nd=10**16;#concentration\n",
"N=9.65*10**9\n",
"V=4;#voltage\n",
"E=10.53*10**-13;#constant\n",
"T=5*10**-7;#time\n",
"q=1.6*10**-19;#charge\n",
"\n",
"#calculation\n",
"W=(2*E*(Na+Nd)/(q*Na*Nd)*(.0259*log(Na*Nd/N**2)+V))**.5;#width\n",
"J=q*N*W/T;#current density\n",
"\n",
"#result\n",
"print\"generation current density is\",round(J,9),\"A/cm^2\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"generation current density is 2.68e-07 A/cm^2\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4.7 Page115"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"Nd=8*10**15;#concentration\n",
"V=1.00;#voltage\n",
"L=5*10**-4;#length of holes\n",
"q=1.6*10**-19;#charge\n",
"N=9.65*10**9\n",
"\n",
"#calculation\n",
"Q=q*L*N**2/Nd*(e**(1/.0259)-1);#minority carriers\n",
"\n",
"#result\n",
"print\"stored minority carriers is\",round(Q,2),\"C/cm^2\"\n",
"print\"the answer in book is slightly wrong\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"stored minority carriers is 0.05 C/cm^2\n",
"the answer in book is slightly wrong\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example4.8, Page120"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"Nd=5*10**16;#concentration\n",
"E=10.53*10**-13;#constant\n",
"N=5.7*10**5\n",
"q=1.6*10**-19;#charge\n",
"\n",
"#calculation\n",
"Vb=E*N**2/2/q/Nd;#breakdown voltage\n",
"\n",
"#result\n",
"print\"breakdown voltage is\",round(Vb,1),\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"breakdown voltage is 21.4 V\n"
]
}
],
"prompt_number": 34
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example4.9 Page122"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"Nb=8*10**14;#concentration\n",
"E=8.85*10**-14;#constant\n",
"q=1.6*10**-19;#charge\n",
"V=500;#voltage\n",
"W=20*10**-4;#width\n",
"\n",
"#calculation\n",
"Wm=(24.8*E*V/q/Nb)**.5;#width\n",
"Vb=V*(W/Wm)*(2-(W/Wm));#breakdown voltage\n",
"\n",
"#result\n",
"print\"width is\",round(Wm*10**4,1),\"micro-m\"\n",
"print\"breakdown voltage is\",round(Vb,3),\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"width is 29.3 micro-m\n",
"breakdown voltage is 449.771 V\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example4.10 Page126"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variable\n",
"from math import *\n",
"V=1.60;#voltage\n",
"C1=10**16;#concentration\n",
"C2=3*10**19;#concentration\n",
"D1=12.00;#dielectric constant\n",
"D2=13.00;#dielectric constant\n",
"E=8.85*10**-14;#constant\n",
"q=1.6*10**-19;#charge\n",
"\n",
"#calculation\n",
"V1=D2*C2*V/(D1*C1+D2*C2);#voltage\n",
"V2=D1*C1*V/(D1*C1+D2*C2);#voltage\n",
"W1=(2*D1*D2*E*C2*V/(C1*D1+C2*D2)/q/C1)**.5;#depletion width\n",
"W2=(2*D1*D2*E*C1*V/(C1*D1+C2*D2)/q/C2)**.5;#depletion width\n",
"\n",
"#result\n",
"print\"electrostatic potential 1 is\",round(V1,2),\"V\"\n",
"print\"electrostatic potential 2 is\",round(V2,5),\"V\"\n",
"print\"depletion width 1 is\",round(W1,8),\"cm\"\n",
"print\"depletion width 2 is\",round(W2,11),\"cm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"electrostatic potential 1 is 1.6 V\n",
"electrostatic potential 2 is 0.00049 V\n",
"depletion width 1 is 4.608e-05 cm\n",
"depletion width 2 is 1.536e-08 cm\n"
]
}
],
"prompt_number": 11
}
],
"metadata": {}
}
]
}
|
