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|
{
"metadata": {
"name": "",
"signature": "sha256:1378ee9b7b5e64639ff100ad2dca16b71e72eadb106daabd3ad20e87834e8b65"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 2 Work, Energy and Power"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.1 Page no 26"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"F=(6,2) #Constant force in vector form 6i+2j in N\n",
"s=(3,5) #Displacement in vector form 3i+5j in N\n",
"\n",
"#Calculations\n",
"import math\n",
"W=(F[0]*s[0])+(F[1]*s[1])\n",
"q=math.acos(W/(math.sqrt(F[0]**2+F[1]**2)*math.sqrt(s[0]**2+s[1]**2)))*180/3.14\n",
"\n",
"#Output\n",
"print\"Workdone by the force is \",W,\"J\" \n",
"print\"Angle between Force and displacement is \",round(q,1),\"degrees\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Workdone by the force is 28 J\n",
"Angle between Force and displacement is 40.6 degrees\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.2 Page no 26"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"m=10 #Mass of block in kg\n",
"q=40 #Angle made by the force with horizontal in degrees\n",
"s=5 #Horizontal displacement of the block in m\n",
"u=0.3 #Coefficient of kinematic friction \n",
"\n",
"#Calculations\n",
"import math\n",
"F=(u*m*9.8)/(math.cos(q*3.14/180.0)+(u*math.sin(q*3.14/180.0)))\n",
"W=(F*math.cos(q*3.14/180.0))*s\n",
"\n",
"#Output\n",
"print\"Workdone by the pulling force is \",round(W,1),\"J\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Workdone by the pulling force is 117.5 J\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.3 Page no 27"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#plot\n",
"import matplotlib.pyplot as plt\n",
"fig = plt.figure()\n",
"x=[0,1,2,3,4,5]\n",
"F=[0,6,6,12,12,0]\n",
"xlabel(\"x (m)\") \n",
"ylabel(\"F (N)\") \n",
"plt.xlim((0,5))\n",
"plt.ylim((0,14))\n",
"a=plot(x,F)\n",
"show(a)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"metadata": {},
"output_type": "display_data",
"png": 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bt1I5pXgvHpt+xty6lcqrPj83FTb9jF1/PaxbBxdfHLsSSXkbPx5OPjmta/Y9kZuh5cvD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\nJEmSJCk5/w8BWpyAvuV2cgAAAABJRU5ErkJggg==\n",
"text": [
"<matplotlib.figure.Figure at 0x883ac30>"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.4 Page no 27"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"m=0.05 #Mass of the body in kg\n",
"v=(3,5) #Velocity in vector form 3i+4j in m/s\n",
"\n",
"#Calculations\n",
"ke=(1/2.0)*m*(v[0]**2+v[1]**2)\n",
"\n",
"#Output\n",
"print\"Kinetic energy is \",ke,\"J\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Kinetic energy is 0.85 J\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.5 Page no 27"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"k=50 #Spring force constant in N/m\n",
"x=-0.02 #Length of compression in m\n",
"\n",
"#Calculations\n",
"W=(1/2.0)*k*(x)**2\n",
"\n",
"#Output\n",
"print\"Work done by the spring when the block comes from the compressed position to the equilibrium position is \",W,\"J\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Work done by the spring when the block comes from the compressed position to the equilibrium position is 0.01 J\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.6 Page no 27"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"x=0.03 #Length stretched by the spring in m\n",
"m=0.25 #Mass of the body in kg\n",
"\n",
"#Calculations\n",
"k=(m*9.8)/x\n",
"\n",
"#Output\n",
"print\"Force constant of the spring is \",round(k,3),\"N/m\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Force constant of the spring is 81.667 N/m\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.7 Page no 27"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"m=5 #Mass of block in kg\n",
"F=20 #Constant force in N\n",
"x=6 #Distance moved by the block in m\n",
"\n",
"#Calculations\n",
"import math\n",
"W=(F*x)\n",
"v=math.sqrt((2*W)/m)\n",
"\n",
"#Output\n",
"print\"Speed of the block when it moves through a distance of \",x,\"m is\",round(v,2),\"m/s\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Speed of the block when it moves through a distance of 6 m is 6.93 m/s\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2.8 Page no 28"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"m=50 #Mass of the object in kg\n",
"v=8 #Speed in m/s\n",
"t=4 #Time taken in s\n",
"\n",
"#Calculations\n",
"a=(v-0)/t\n",
"s=(v**2/(2.0*a))\n",
"W=(m*a*s)\n",
"P=(W/t)\n",
"\n",
"#Output\n",
"print\"Workdone on the object is \",W,\"J\" \n",
"print\"The average power delivered by the force in the first \",t,\"s is \",P,\"watt\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Workdone on the object is 1600.0 J\n",
"The average power delivered by the force in the first 4 s is 400.0 watt\n"
]
}
],
"prompt_number": 8
}
],
"metadata": {}
}
]
}
|