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{
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{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 12:Thermodynamics"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex12.1:pg-413"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The work done by the gas is= -220.0 J\n"
]
}
],
"source": [
" import math #Example 12_1\n",
" \n",
" \n",
" #To find the work done by the gas\n",
"d1=800 #Units in meter**3\n",
"d2=500 #Units in meter**3\n",
"p1=5*10**5 #Units in Pa\n",
"w1=p1*(d1-d2)*10**-6 #Units in J\n",
"p2=2*10**5 #Units in Pa\n",
"d3=200*10**-6 #Units in meter**3\n",
"p3=3*10**5 #Units in Pa\n",
"w2=(p2*d3)+(0.5*p3*d3) #Units in J\n",
"print \"The work done by the gas is=\",round(-(w1+w2)),\" J\"\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex12.2:pg-415"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The estimated Cv value of nitric acid is Cv= 693.0 J/Kg K\n"
]
}
],
"source": [
" import math #Example 12_2\n",
" \n",
" \n",
" #To estimate the Cv of nitric acid\n",
"r=8314 #Units in J/Kmol K\n",
"m=30 #Units in Kg/Kmol\n",
"Cv=2.5*(r/m) #Units in J/Kg K\n",
"print \"The estimated Cv value of nitric acid is Cv=\",round(Cv),\" J/Kg K\"\n",
" #in textbook the answer is printed wrong as Cv=690 J/Kg K correct answer is 692 J/Kg K\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex12.3:pg-415"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The final temperature is T2= 886.0 K\n"
]
}
],
"source": [
" import math #Example 12_3\n",
" \n",
" \n",
" #To find the final temperature\n",
"t1=27 #units in Centigrade\n",
"t1=t1+273 #Units in K\n",
"gama=1.4 #Units in Constant\n",
"p1=1 #units in Pa\n",
"v1_v2=15 #Units of in ratio\n",
"logT2=math.log10(t1)-((gama-1)*(math.log10(p1)-math.log10(v1_v2)))\n",
"T2=10**logT2 #Uniys in K\n",
"print \"The final temperature is T2=\",round(T2),\" K\"\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex12.4:pg-417## "
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"This type of process is termed as throttling process and described by the equation Delta U=- Delta W\n",
"\n",
"Where Delta W is the work done\n"
]
}
],
"source": [
" import math #Example 12_4\n",
" \n",
" \n",
" #To describe the Temperature changes of the gas\n",
"print \"This type of process is termed as throttling process and described by the equation Delta U=- Delta W\\n\"\n",
"print \"Where Delta W is the work done\"\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex12.5:pg-418## "
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The entropy is Delta S= 24.5 J/K\n"
]
}
],
"source": [
" import math #Example 12_5\n",
" \n",
" \n",
" #To findout by how much the entropy of the system changes\n",
"m=20 #Units in gm\n",
"alpha=80 #Units in cal/gm\n",
"t=4.184 #Units in J/Cal\n",
"Q=m*alpha*t #Units in J\n",
"T=273 #Units in K\n",
"S=Q/T #Units in J/K\n",
"print \"The entropy is Delta S=\",round(S,1),\" J/K\"\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Ex12.6:pg-419## "
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"The amount of Electricity is required is Delta W= 11666.0 J\n"
]
}
],
"source": [
" import math #Example 12_6\n",
" \n",
" \n",
" #To findout how much electricity is needed\n",
"Tc=278 #Units in K\n",
"Th=293 #Units in K\n",
"COP=Tc/(Th-Tc) #Units in ratio\n",
"Qc=210000 #Units in J\n",
"W=Qc/COP #Units in J\n",
"print \"The amount of Electricity is required is Delta W=\",round(W),\" J\"\n"
]
}
],
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|
