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{
"metadata": {
"name": "",
"signature": "sha256:041d5244aa5d603722207511a0c716199565294cf0a34c3074cf07858de21983"
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"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 8 : Magnetic properties and conductivity"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.3 Page No : 354"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\n",
"# Given\n",
"Mat = 55.85*10**-3 # in Kg/mol\n",
"NA = 6.022*10**23 # in mol**-1\n",
"p = 7.86*10**3 # in kg/m3\n",
"Msat = 1.75*10**6 # in A/m\n",
"# funcprot(0)\n",
"beta = 9.27*10**-24 # in J/tesla\n",
"\n",
"# Calculations and Results\n",
"n_at = p*NA/Mat\n",
"x = Msat/(n_at*beta)\n",
"print(\"In the solid each Fe atom contributes only {0:.4f} bohr magneton\".format(x))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"In the solid each Fe atom contributes only 2.2275 bohr magneton\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.5 Page No : 358"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\n",
"# Given\n",
"u_o = 4*math.pi*10**-7 # in H/m\n",
"u_ri = 2*10**3\n",
"N = 200.0 # no. of turns\n",
"d = 0.005 # in m\n",
"D = 2.5*10**-2 # in m\n",
"\n",
"# Calculations and Results\n",
"A = math.pi*(d**2)/4\n",
"l = math.pi*D\n",
"L = u_ri*u_o*N**2*A/l\n",
"print(\"Approximate inductance of the coil in Henry is {0:.4f}\".format(L))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Approximate inductance of the coil in Henry is 0.0251\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.7 Page No : 359"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\n",
"# Given\n",
"N = 500.0 # no.of turns\n",
"B = 5.0 # in Tesla\n",
"l = 1.0 # in m\n",
"r = 10**-3 # in m\n",
"uo = 4*math.pi*10**-7 # in H/m\n",
"d = 10*10**-2 # in m\n",
"\n",
"# Calculations and Results\n",
"I = (B*l)/(uo*N)\n",
"print(\"current in Amperes is {0:.4f}\".format(I))\n",
"E_vol = B**2/(2*uo)\n",
"v = math.pi*l*d**2/4.0\n",
"E = E_vol*v\n",
"print(\"Energy stored in the solenoid in joules is {0:.4f}\".format(E))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"current in Amperes is 7957.7472\n",
"Energy stored in the solenoid in joules is 78125.0000\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|
