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{
"metadata": {
"name": "",
"signature": "sha256:0e14a7576f4038d6474523e0faf6c534de06cbb509045bb799ae70b4aaeef049"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter8-See page"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg203"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#calculate rate of water flow\n",
"##initialisation of variables\n",
"H1= 12. ##in\n",
"H2= 20. ##in\n",
"z= 8. ##in\n",
"h1= 24. ##in\n",
"h= 20. ##in\n",
"k1= 0.026 ##in/sec\n",
"D= 3. ##in\n",
"##calculations\n",
"k2= H2*k1/((z/(1.-h/h1))-H1)\n",
"i= h1/(H1+H2)\n",
"A= math.pi/4.*D**2\n",
"keq= (H1+H2)/((H1/k1)+(H2/k2))\n",
"q= keq*A*i*3600.\n",
"##results\n",
"print'%s %.2f %s'% ('rate of water flow = ',q,' in^3/hr ')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"rate of water flow = 330.81 in^3/hr \n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2-pg208"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate a)How high (above the ground surface) the water will rise if piezometers are placed at points aandb.\n",
"#b.The total rate of seepage through the permeable layer per unit length\n",
"#c. The approximate average hydraulic gradient at c.\n",
"##initialisation of variables\n",
"Nd= 6.\n",
"H1= 5.6 ##m\n",
"H2= 2.2 ##m\n",
"k= 5e-5 ##cm/sec\n",
"dL= 4.1 ##m\n",
"##calculations\n",
"H= (H1-H2)/Nd\n",
"h1= 5.61-H\n",
"h2= 5.61-5.*H\n",
"q= 2.38*(H1-H2)*k/Nd\n",
"i= H/dL\n",
"##results\n",
"print'%s %.3f %s'% ('at point a,water will rise to height of = ',h1,' m ')\n",
"print'%s %.3f %s'% ('at point b,water will rise to height of =',h2,' m ')\n",
"print'%s %.e %s'% ('total rate of seepage per unit lenghth = ',q,' m^3/sec/m ')\n",
"print'%s %.3f %s'% ('average hydraulic gradient at c = ',i,' ')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"at point a,water will rise to height of = 5.043 m \n",
"at point b,water will rise to height of = 2.777 m \n",
"total rate of seepage per unit lenghth = 7e-05 m^3/sec/m \n",
"average hydraulic gradient at c = 0.138 \n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex3-pg210"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#calculate average rate of flow\n",
"##initialisation of variables\n",
"k1= 5.67 ##ft/day\n",
"k2= 11.34 ##ft/day\n",
"##from graph\n",
"Nd= 8\n",
"Nf= 2.5\n",
"H= 20\n",
"##calculations\n",
"q= math.sqrt(k1*k2)*H*Nf/Nd\n",
"##results\n",
"print'%s %.2f %s'% ('average rate of flow = ',q,' ft^3/day/ft ')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"average rate of flow = 50.12 ft^3/day/ft \n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex4-pg 212"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#calculate seepage under the dam \n",
"##initialisation of variables\n",
"B= 6. ##m\n",
"L= 120. ##m\n",
"s= 3. ##m\n",
"T= 6. ##m\n",
"x= 2.4 ##m\n",
"H= 5. ##m\n",
"k= 0.008 ##cm/sec\n",
"##calculations\n",
"b=B/2.\n",
"a1= b/T\n",
"a2= s/T\n",
"a3= x/b\n",
"Q= 0.378*k*H*L*36*24\n",
"##results\n",
"print'%s %.2f %s'% ('seepage under the dam = ',Q,' m^3/day ')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"seepage under the dam = 1567.64 m^3/day \n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex5-pg217"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#calculate seepage rate\n",
"##initialisation of variables\n",
"b= math.pi/4. ##degrees\n",
"a= math.pi/6.##degrees\n",
"B= 10. ##ft\n",
"H= 20. ##ft\n",
"h= 25. ##ft\n",
"k= 2e-4 ##ft/min\n",
"##calculations\n",
"r= H/math.tan(b)\n",
"d= 0.3*r+(h-H)/math.tan(b)+B+h/math.tan(a)\n",
"L= d/math.cos(a)-math.sqrt((d/math.cos(a))**2-(H/math.sin(a))**2)\n",
"q= k*L*math.tan(a)*math.sin(a)*24.*60\n",
"##results\n",
"print'%s %.4f %s'% ('seepage rate = ',q,' ft^3/day/ft ')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"seepage rate = 0.9724 ft^3/day/ft \n"
]
}
],
"prompt_number": 6
}
],
"metadata": {}
}
]
}
|
