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{
"metadata": {
"name": "",
"signature": "sha256:cc62756cbf06ddef68226804d15a2efed303c30289a23f7a88b85756c1a62af7"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter12-Shear Strength of Soil"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg378"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#Determine the relationships for peak shear strength(tf) and residual shear strength(tr).\n",
"D=50 ## in mm\n",
"A= math.pi/4. *(D/1000.)**2\n",
"## solving for test 1 \n",
"N=150.\n",
"Sp=157.5\n",
"Sr=44.2\n",
"Tf=Sp/A\n",
"Tr=Sr/A\n",
"## from graph\n",
"k=math.tan(27/57.3)\n",
"k1=math.tan(14.6/57.3)\n",
"\n",
"print'%s %.3f %s'%('Peak strength Tf = 40+ t*',k,'')\n",
"print'%s %.3f %s'%(' Residual strength Tr = t*',k1,'')\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Peak strength Tf = 40+ t* 0.509 \n",
" Residual strength Tr = t* 0.260 \n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2-pg385"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#Determine\n",
"#a.Angle of friction,f\u0004\n",
"#b.Angleuthat the failure plane makes with the major principal plane\n",
"T3=16. ## lb/in^2\n",
"Tf=25. ## lb/in^2\n",
"T1=T3+Tf\n",
"a= math.asin((T1-T3)/(T1+T3))*57.3 ## Mohr's circle\n",
"print'%s %.2f %s'%('a)Angle of friction,a = ',a,'')\n",
"b= 45.+ a/2.\n",
"print'%s %.2f %s'%(' b)Angle b that the failure plane makes with the major principal plane = ',b,'')\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"a)Angle of friction,a = 26.02 \n",
" b)Angle b that the failure plane makes with the major principal plane = 58.01 \n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex3-pg386"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#Find the normal stress s\u0004and the shear stress tfon the failure plane.\n",
"#b.Determine the effective normal stress on the plane of maximum shear stress\n",
"T1=41.\n",
"T3=16.\n",
"a=58.\n",
"T=(T1+T3)/2. + (T1-T3)*math.cos(2.*a/57.3)/2.\n",
"tf=(T1-T3)*math.sin(2.*a/57.3)/2\n",
"print'%s %.2f %s'%('a)the normal stress T = ',T,' lb/in^2')\n",
"print'%s %.2f %s'%('(b) and the shear stress tf = ',tf,' lb/in^2')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"a)the normal stress T = 23.02 lb/in^2\n",
"(b) and the shear stress tf = 11.24 lb/in^2\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex4-pg387"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#The equation of the effective stress failure envelope for normally consolidated clayey soilistf \u0001s\u0004tan 30\u0005. A drained triaxial test was conducted with the same soil at a chamberconfining pressure of 10 lb/in.2Calculate the deviator stress at failure.\n",
"##For normally consolidated clay, c' \u0004= 0.\n",
"a=30.\n",
"T3=10.\n",
"T1=T3*(math.tan(60/57.3))**2\n",
"Tf=T1-T3\n",
"print'%s %.2f %s'%('The deviator stress at failure = ',Tf,' lb/in^2')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The deviator stress at failure = 19.99 lb/in^2\n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex5-pg387"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#Determine the shear strength parameters.\n",
"T13=70.\n",
"T1f=130.\n",
"T11=T13+T1f\n",
"\n",
"T23=160.\n",
"T2f=223.5\n",
"T21=T23+T2f\n",
"\n",
"a= 2*(math.atan(((T11-T21)/(T13-T23))**0.5) *57.3-45)\n",
"c= (T11-T13*((math.tan((45+a/2.)/57.3))**2)/(2*math.tan(45+a/2.)/57.3))\n",
"d=c-267\n",
"print('the shear strength parameter d = ',d,' kN/m^2')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"('the shear strength parameter d = ', 20.686836038348247, ' kN/m^2')\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex6-pg394"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#a.Consolidated-undrained angle of shearing resistance,f\n",
"#b.Drained friction angle,f\u0004\n",
"T3=12.\n",
"Tf=9.1\n",
"T1=T3+Tf\n",
"u=6.8\n",
"a=math.asin((T1-T3)/(T1+T3))\n",
"\n",
"a1= math.asin((T1-T3)/(T1+T3-2*u))\n",
"\n",
"print'%s %.1f %s'%('a)Consolidated-undrained angle of shearing resistance = ',a*57.3,' degrees')\n",
"print'%s %.1f %s'%(' b)Drained friction angle =',a1*57.3,' degrees')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"a)Consolidated-undrained angle of shearing resistance = 16.0 degrees\n",
" b)Drained friction angle = 27.8 degrees\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex7-pg395"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#What would be the deviatorstress at failure, (\u0010sd)f, if a drained test was conducted with the same chamber allaround pressure (that is, 12 lb/in.2)?\n",
"T3=12.\n",
"a=27.8\n",
"T1=T3*(math.tan(59./57.3))**2\n",
"Tf=T1-T3\n",
"print'%s %.1f %s'%('the deviator stress at failure = ',Tf,' lb/in^2')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the deviator stress at failure = 21.2 lb/in^2\n"
]
}
],
"prompt_number": 15
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex8-pg400"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#Estimate the average undrained shear strength of the clay [that is,cu(VST)].\n",
"PI=28.\n",
"OCR=3.2\n",
"To=160.\n",
"Kn=0.11+0.0037*PI\n",
"Ko=OCR**0.8 * Kn\n",
"Cu=Ko*To\n",
"print'%s %.1f %s'%('the average undrained shear strength of the clay =',Cu,' kN/m^2')\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"the average undrained shear strength of the clay = 86.7 kN/m^2\n"
]
}
],
"prompt_number": 16
}
],
"metadata": {}
}
]
}
|
