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{
"metadata": {
"name": "",
"signature": "sha256:3f5444f542f0d6a3b857b61fbecdc4e8047247ed8828d4cea5a34f91ccdf5eb3"
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 1:Geotechnical Properties of Soil"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.1:Pg-10"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 1.1\n",
"\n",
"V=0.25; # ft^3\n",
"W=30.8; #lb\n",
"Wd=28.2; # weight dried lb\n",
"Gs=2.7;\n",
"Gammaw=62.4; #lb/ft^3\n",
"Gamma=W/V;\n",
"print Gamma,\" is moist unit weight in lb/ft^3\"\n",
"w=(W-Wd)/W;\n",
"print round(w*100,2),\"is moisture content in %\"\n",
"Gammad=Wd/V;\n",
"print Gammad, \"is dry unit weight in lb/ft^3\"\n",
"Vs=Wd/Gs/Gammaw;\n",
"Vv=V-Vs;\n",
"e=Vv/Vs;\n",
"print round(e,3),\" is void ratio\"\n",
"n=e/(1+e);\n",
"print round(n,2),\"is porosity\"\n",
"Vw=(W-Wd)/Gammaw;\n",
"S=Vw/Vv;\n",
"print round(S*100,2),\"is saturation in %\"\n",
"\n",
"# The answers in the book are different due to approximation while here calculations are precise\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"123.2 is moist unit weight in lb/ft^3\n",
"8.44 is moisture content in %\n",
"112.8 is dry unit weight in lb/ft^3\n",
"0.494 is void ratio\n",
"0.33 is porosity\n",
"50.43 is saturation in %\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.2:Pg-11"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 1.2\n",
"\n",
"e=0.72;\n",
"w=12.0/100; #moisture content\n",
"Gs=2.72;\n",
"Gammaw=9.81;#kN/m^3\n",
"Gammad=Gs*Gammaw/(1+e);\n",
"print round(Gammad,2),\"= dry unit weight in kN/m^3\"\n",
"Gamma=Gs*Gammaw*(1+w)/(1+e);\n",
"print round(Gamma,2),\" = moist unit weight in kN/m^3\"\n",
"Gammasat=(Gs+e)*Gammaw/(1+e);\n",
"wa=Gammasat-Gamma;#water added\n",
"print round(wa,2),\" = water added in kN/m^3\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"15.51 = dry unit weight in kN/m^3\n",
"17.38 = moist unit weight in kN/m^3\n",
"2.24 = water added in kN/m^3\n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.3:Pg-12"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 1.3\n",
"from scipy.optimize import fsolve\n",
"gmax=17.1; # Gammadmax\n",
"Dr=0.7;\n",
"w=8.0/100;#moisture content\n",
"gmin=14.2; #Gammadmin\n",
"def f(x):\n",
" return (x-14.2)/(17.1-14.2)*17.1/x-0.7 \n",
"x=fsolve(f,16);#solving for gammad\n",
"Gamma=x[0]*(1+w);\n",
"print round(Gamma,2),\"moist unit weight in kN/m^3\"\n",
"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"17.4 moist unit weight in kN/m^3\n"
]
}
],
"prompt_number": 14
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.7:Pg-38"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 1.7\n",
"import math\n",
"#part (a)\n",
"e1=0.92;\n",
"e2=0.86;\n",
"Hc=2.8; # in m\n",
"s2=212.0;#sigma2dash Load in kN/m2\n",
"s1=140.0;#sigma1dash Load in kN/m2\n",
"Cc=(e1-e2)/math.log10(s2/s1);\n",
"Sc=Cc*Hc/(1+e1)*math.log10(s2/s1);\n",
"print Sc*1000,\"consolidated depth in mm\"\n",
"#part (b)\n",
"# from Figure (1.21):\n",
"Sct=40.0;# in mm\n",
"T50=0.197;\n",
"t=4.5; # in MIN\n",
"Cr=T50*12.7**2.0/t;\n",
"U=Sct/Sc*100.0/1000;\n",
"H=Hc/2;\n",
"Tv=math.pi/4*U**2.0/100**2;\n",
"t=Tv*H**2.0/Cr*1000.0**2/60.0/24;\n",
"print round(t,1),\" is time required in days\"\n",
"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"87.5 consolidated depth in mm\n",
"31.6 is time required in days\n"
]
}
],
"prompt_number": 27
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1.8:Pg-42"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#example 1.8\n",
"\n",
"Cv=7.061; # in mm^2/min\n",
"tc=15*24*60.0;\n",
"H=2.8/2*1000.0;\n",
"Scmax=87.5; # consolidation\n",
"Tc=Cv*tc/H**2;\n",
"tv=31.6*24*60;\n",
"Tv=Cv*tv/H**2;\n",
"#from figure 1.28\n",
"Sct=Scmax*0.36;\n",
"print Sct,\"is consolidation in 31.6 days in mm\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"31.5 is consolidation in 31.6 days in mm\n"
]
}
],
"prompt_number": 28
}
],
"metadata": {}
}
]
}
|
