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{
"metadata": {
"name": "",
"signature": "sha256:8aef1c332f2a49ead17fadd51ccfa9b15c7423655061dea702b72eda65234123"
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 6 FM Circuits"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.1 Page no 178"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"Vc =40*10**-12\n",
"c = 20*10**-12\n",
"f0 = 5.5*10**6\n",
"Ct = Vc+c\n",
"\n",
"#Calculation\n",
"L = 1/((6.28*f0)**2*Ct)\n",
"\n",
"#Result\n",
"print\"The value of the inductance is \",round(L*10**6,0),\"microhenry\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of the inductance is 14.0 microhenry\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.2 Page no 186"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"f=168.96*10**6\n",
"multiplier=24.0\n",
"deviation = 5*10**3\n",
"fm = 2.8*10**3\n",
"\n",
"#Calculation\n",
"f0 =f/multiplier\n",
"fd= deviation/multiplier\n",
"phaseshift = fd/fm\n",
"phaseshift_degrees = phaseshift*57.3\n",
"total_phaseshift =2*phaseshift_degrees\n",
"\n",
"#Result\n",
"print\"(a) The crystal oscillator frequency is \",f0/10**6,\"MHz\"\n",
"print\"(b) The total phase shift is \",round(total_phaseshift,3),\"degree\"\n",
"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a) The crystal oscillator frequency is 7.04 MHz\n",
"(b) The total phase shift is 8.527 degree\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6.3 Page no 187"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"R =1*10**3\n",
"phaseshift =4.263\n",
"phaseshift_center= 45\n",
"f =7.04*10**6\n",
"\n",
"#Calculation\n",
"phase_l = phaseshift_center - phaseshift\n",
"phase_u = phaseshift_center + phaseshift\n",
"phaserange_total = phase_u - phase_l\n",
"Xc1 = 1161\n",
"C1 = 1/(6.28*f*Xc1)\n",
"Xc2 = 861\n",
"C2 = 1/(6.28*f*Xc2)\n",
"\n",
"#Result\n",
"print\"The two values of the capacitance to achieve total deviation are \",round(C1*10**12,1),\"pf to\",round(C2*10**12,1),\"pf\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The two values of the capacitance to achieve total deviation are 19.5 pf to 26.3 pf\n"
]
}
],
"prompt_number": 5
}
],
"metadata": {}
}
]
}
|