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{
"metadata": {
"name": "",
"signature": "sha256:163d017a43636b203253208922a2be0b72d9894b37f4d97c9da43a5e9b39c875"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 7 - Gases and Introductory stastical thermodynamics"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2 - pg 192"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the Gas constant\n",
"#Initialization of variables\n",
"h=76. #cm\n",
"d=13.5951 #g/cc\n",
"g=980.655 #cm/s^2\n",
"T=273.15 #K\n",
"v=22414.6 #cm^3 /mol\n",
"#calculations\n",
"P=h*d*g\n",
"R=P*v/(T)\n",
"#results\n",
"print '%s %.3e %s' %(\"Gas constant =\",R,\"ergs/deg. mol\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Gas constant = 8.315e+07 ergs/deg. mol\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3 - pg 192"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the R value in calories\n",
"#Initialization of variables\n",
"cal=4.184*10**7 #ergs\n",
"R=8.315*10**7 #ergs/deg/mol\n",
"#calculations\n",
"Rdash=R/cal\n",
"#results\n",
"print '%s %.3f %s' %(\"R in calories =\",Rdash,\" cal/ deg mol\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"R in calories = 1.987 cal/ deg mol\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4 - pg 192"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the root mean square velocity\n",
"#Initialization of variables\n",
"import math\n",
"from math import sqrt\n",
"R=8.315*10**7 #ergs/deg/mol\n",
"T=273.2 #deg\n",
"M=4 #g/mol\n",
"#calculations\n",
"u2=3*T*R/M\n",
"u=sqrt(u2)\n",
"#results\n",
"print '%s %.2e %s' %(\"root mean square velocity =\",u,\" cm/sec\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"root mean square velocity = 1.31e+05 cm/sec\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5 - pg 194"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the Partial pressure of N2, O2 and CO2\n",
"#Initialization of variables\n",
"n1=2.\n",
"n2=10.\n",
"n3=3.\n",
"P=720. #mm of Hg\n",
"#calculations\n",
"n=n1+n2+n3\n",
"x1=n1/n\n",
"P1=x1*P\n",
"x2=n2/n\n",
"P2=x2*P\n",
"x3=n3/n\n",
"P3=x3*P\n",
"#results\n",
"print '%s %d %s' %(\"\\n Partial pressure of N2 =\",P1,\"mm\")\n",
"print '%s %d %s' %(\"\\n Partial pressure of O2 =\",P2,\" mm\")\n",
"print '%s %d %s' %(\"\\n Partial pressure of CO2 =\",P3,\"mm\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
" Partial pressure of N2 = 96 mm\n",
"\n",
" Partial pressure of O2 = 480 mm\n",
"\n",
" Partial pressure of CO2 = 144 mm\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6 - pg 197"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the Total energy\n",
"#Initialization of variables\n",
"T=273.2+25 #K\n",
"n=1 #mol\n",
"R=1.987 #cal/deg mol\n",
"#calculations\n",
"Etr=1.5*n*R*T\n",
"Erot=1.5*n*R*T\n",
"Evib=0\n",
"Eel=0\n",
"Etot=Etr+Erot+Evib+Eel\n",
"#results\n",
"print '%s %d %s' %(\"Total energy =\",Etot,\"cal\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Total energy = 1777 cal\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7 - pg 199"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the Molecular diameter of He\n",
"#Initialization of variables'\n",
"import math\n",
"b=24.1 #cm^2/mol\n",
"N=6.023*10**23 #mole^-1\n",
"#calculations\n",
"d=(3*b/(2*math.pi*N))**(1./3)\n",
"#results\n",
"print '%s %.2e %s' %(\"Molecular diameter of He =\",d,\" cm\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Molecular diameter of He = 2.67e-08 cm\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8 - pg 205"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the Volume\n",
"#Initialization of variables\n",
"P=100. #atm\n",
"T=200. #K\n",
"n=1. #mole\n",
"R=0.08206 #l atm/deg mol\n",
"print \"From psychrometric charts,\"\n",
"Tc=126.2 #K\n",
"Pc=33.5 #K\n",
"#calculations\n",
"Pr=P/Pc\n",
"Tr=T/Tc\n",
"print \"From z charts,\"\n",
"z=0.83\n",
"V=z*n*R*T/P\n",
"#results\n",
"print '%s %.3f %s' %(\"Volume =\",V,\" liter\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"From psychrometric charts,\n",
"From z charts,\n",
"Volume = 0.136 liter\n"
]
}
],
"prompt_number": 7
}
],
"metadata": {}
}
]
}
|
