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{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 1 : Introduction to Equilibrium"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 1.1 Page: 9"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math \n",
"\n",
"m_i = 10. #[g]\n",
"m_w = 990. #[g]\n",
"M_i = 342.3 #[g]\n",
"M_w = 18. #[g]\n",
"\n",
"\n",
"x_i = m_i/(m_i+m_w)\n",
"x_i = x_i*100. # [in percentage]\n",
"\n",
"n_i = m_i/M_i # number of moles of sucrose\n",
"n_w = m_w/M_w # number of moles of water\n",
"x_j = n_i/(n_i+n_w)\n",
"x_j = x_j*100 # [in percentage]\n",
"\n",
"m = n_i/m_w*1000 #[molal]\n",
"x_ppm = x_i*10**(6)/100. #[ppm]\n",
"\n",
"print \" sucrose concentration in terms of the mass fraction is %f%%\"%(x_i)\n",
"print \" sucrose concentration in terms of the mole fraction is %f%%\"%(x_j)\n",
"print \" sucrose concentration in terms of the molality is %f molal\"%(m)\n",
"print \" sucrose concentration in terms of the ppm is %f ppm\"%(x_ppm)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" sucrose concentration in terms of the mass fraction is 1.000000%\n",
" sucrose concentration in terms of the mole fraction is 0.053088%\n",
" sucrose concentration in terms of the molality is 0.029509 molal\n",
" sucrose concentration in terms of the ppm is 10000.000000 ppm\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 1.2 Page: 9"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math \n",
"\n",
"T = 20. #[C]\n",
"d = 1.038143/1000*10.**(6) #[kg/m**(3)]\n",
"m_i = 10. #[g] mass of sucrose\n",
"M_i = 342.3 #[g/mol] molecular weight of sucrose\n",
"\n",
"m = 1.00 #[kg]\n",
"V = m/d*1000 #[L]\n",
"\n",
"m_1 = m_i/V #[g/L]\n",
"\n",
"\n",
"m_2 = (m_i/M_i)/V #[mol/L]\n",
"\n",
"print \" Mass concentration of the solution is %f g/L\"%(m_1)\n",
"print \" Mole concentration of the solution is %f mol/L\"%(m_2)\n",
"\n",
"print \" Molarity of the solution is %f mol/L\"%(m_2)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Mass concentration of the solution is 10.381430 g/L\n",
" Mole concentration of the solution is 0.030328 mol/L\n",
" Molarity of the solution is 0.030328 mol/L\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
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"metadata": {}
}
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|
