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{
"metadata": {
"name": "",
"signature": "sha256:b4c2ad3d2231e003dd81c8536584a68dd7b730bbf60d4fc7279f9c5e2add3106"
},
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 24 Superconductivity"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 24.1 Page no 289"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"H1=1.4*10**5 #A/m\n",
"H2=4.2*10**5 \n",
"T1=14 #K\n",
"T2=13\n",
"Tc=14.5\n",
"H0=20.66*10**5 #A/m\n",
"T=4.2\n",
"\n",
"#Calculation\n",
"Hc=H0*(Tc**2-T**2)/Tc**2\n",
"\n",
"#Result\n",
"print\"Critical field is\",round(Hc*10**-5,1),\"*10**5 A/m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Critical field is 18.9 *10**5 A/m\n"
]
}
],
"prompt_number": 36
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 24.2 Page no 290"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"Tc1=4.185 #K\n",
"M1=199.5\n",
"M2=203.4\n",
"\n",
"#Calculation\n",
"import math\n",
"Tc2=Tc1*math.sqrt(M1)/math.sqrt(M2)\n",
"\n",
"#Result\n",
"print\"Critical temperature is\",round(Tc2,2),\"K\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Critical temperature is 4.14 K\n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 24.3 Page no 290"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"T=4.2 #K\n",
"H0=6.5*10**4 #A/m\n",
"Tc=7.18\n",
"d=10**-3\n",
"\n",
"#Calculation\n",
"Hc=H0*(Tc**2-T**2)/Tc**2\n",
"Jc=4*Hc/d\n",
"\n",
"#Result\n",
"print\"Critical current is\", round(Jc*10**-8,3),\"*10**8 A/m**2\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Critical current is 1.71 *10**8 A/m**2\n"
]
}
],
"prompt_number": 26
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 24.4 Page no 291"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"w=750 #A\n",
"T=3.5\n",
"Tc=4.12\n",
"h=6.02*10**26\n",
"a=13.55*10**3\n",
"M=200.6\n",
"\n",
"#Calculation\n",
"import math\n",
"W=w*math.sqrt(1-(T/Tc)**4)\n",
"n0=h*a/M\n",
"ns=n0*(1-(T/Tc)**4)\n",
"\n",
"#Result\n",
"print\"Penetration is\", round(ns*10**-28,2)*10**28,\"/m**3\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Penetration is 1.95e+28 /m**3\n"
]
}
],
"prompt_number": 35
}
],
"metadata": {}
}
]
}
|
