1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
|
{
"metadata": {
"name": "",
"signature": "sha256:60e1b4f69268bf5ef981c421da464c3f2155bd9dcb0f2936b64236297523b2ca"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 10 Nuclear Fission and Fusion"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 10.1 Page no 351"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"c=3*10**8 #m/s\n",
"m=3.6*10**-3 #Kg\n",
"a=36000\n",
"\n",
"#Calculation\n",
"E=m*c**2\n",
"E1=E/(a*10**3)\n",
"\n",
"#Result\n",
"print\"Energy is\", E1*10**-6,\"*10**7 Kilo watt-hrs\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Energy is 9.0 *10**7 Kilo watt-hrs\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 10.2 Page no 352"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"mn=1.6747*10**-27\n",
"mp=1.6725*10**-27\n",
"me=9*10**-31\n",
"c=3*10**8\n",
"e=1.6*10**-19\n",
"\n",
"#Calculation\n",
"m=mn-(mp+me)\n",
"E=(m*c**2)/e\n",
"\n",
"#Result\n",
"print\"Energy produced is\", round(E*10**-6,2),\"Mev\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Energy produced is 0.73 Mev\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 10.3 Page no 352"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"P=3.2*10**7 #Watts\n",
"e=1.6*10**-13\n",
"E1=200.0\n",
"a=1000\n",
"N=6.0*10**23\n",
"A=235\n",
"\n",
"#Calculation\n",
"E=P/e\n",
"n=E/E1\n",
"n1=n*a*3600\n",
"m=n1*A/N\n",
"\n",
"#Result\n",
"print\"Number of fission occuring in the reactor/sec is\", n\n",
"print\"Mass of U235 used in 1000 hrs is\",m*10**-3,\"Kg\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Number of fission occuring in the reactor/sec is 1e+18\n",
"Mass of U235 used in 1000 hrs is 1.41 Kg\n"
]
}
],
"prompt_number": 28
}
],
"metadata": {}
}
]
}
|
