1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
|
{
"metadata": {
"name": "MP-8"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": "Many Electron Atoms"
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 8.1 Page 248"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nhc=1240.0*10**-9;Rinfi=1.097*10**7;Z=11; #for sodium atom;and other constants in MeV\n\n#calculation\ndelE=3*hc*Rinfi*(Z-1)**2/4.0 #change in energy\n\n#result\nprint\"The energy of the Ka x-ray of the sodium atom in KeV.is\",round(delE/10**3,3);\n",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "The energy of the Ka x-ray of the sodium atom in KeV.is 1.02\n"
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 8.2 Page 249"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nEKa=21.990;EKb=25.145;EK=25.514 #all the values are in KeV\n\n#calcualtion\nELo=EKb-EKa;\n\n#result\nprint\"The enrgy of La of X-ray in KeV.is\",round(ELo,3); #Energy of La X-ray\n\n#partb\nEL=-EK+EKa;\n\n#result\nprint\"Hence the binding energy of the L electon in KeV.is\",round(EL,3); # for electron L electron",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "The enrgy of La of X-ray in KeV.is 3.155\nHence the binding energy of the L electon in KeV.is -3.524\n"
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 8.3 Page 250"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nl=1.0; \n\n#calculation\nLmax=l+l;Lmin=l-l;\ns=1.0/2; Smax=s+s;Smin=s-s;\n\n#result\nprint\"Value of L ranges from\",Lmin,\" to\",Lmax,\" i.e\",Lmin,1,Lmax;\nprint\"Values of S are maxi,min\",Smax,Smin;\n",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Value of L ranges from 0.0 to 2.0 i.e 0.0 1 2.0\nValues of S are maxi,min 1.0 0.0\n"
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 8.4 Page 250"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nl=1.0; \n\n#calculation\nLmax=l+l;Lmin=l-l;\ns=1.0/2; Smax=s+s;Smin=s-s;\n\n#result\nprint\"Considering any two electrons,Value of L2e ranges from\",Lmin,\" to\",Lmax,\" i.e\",Lmin,1,Lmax;\nprint\"Adding the angular momentum of the third electron to L2emax gives the maximum whole angular momentum as 2+1=3; and subtracting it from L2e=1 gives 0\"\nprint\"Values of S are maxi,min\",Smax,Smin;\nprint\"Adding and subtracting the spin of third to S2e=1 and S2e=0 respectively gives the spins 3/2 and 1/2 for the 3 electron system.\";",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Considering any two electrons,Value of L2e ranges from 0.0 to 2.0 i.e 0.0 1 2.0\nAdding the angular momentum of the third electron to L2emax gives the maximum whole angular momentum as 2+1=3; and subtracting it from L2e=1 gives 0\nValues of S are maxi,min 1.0 0.0\nAdding and subtracting the spin of third to S2e=1 and S2e=0 respectively gives the spins 3/2 and 1/2 for the 3 electron system.\n"
}
],
"prompt_number": 6
}
],
"metadata": {}
}
]
}
|
