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{
"metadata": {
"name": "",
"signature": "sha256:f3dfb0a49e3f8552798e92e62c041d1f0b46371fc7dc05dfc9c1bf5833f43216"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"14: Nuclear Fission And Fusion"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 14.1, Page number 269"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"E1=7.8; #avg. B.E per nucleon(MeV)\n",
"E2=8.6; #for fissin fragments(MeV)\n",
"\n",
"#Calculation\n",
"FER=(234*E2)-(236*E1); #Fission energy released(MeV)\n",
"\n",
"#Result\n",
"print \"Fission energy released is\",FER,\"MeV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Fission energy released is 171.6 MeV\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 14.2, Page number 273"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"m1=235.044; #mass of 92U235(a.m.u)\n",
"m2=97.905; #mass of 42Mo98(a.m.u)\n",
"m3=135.917; #mass of 54Xe136(a.m.u)\n",
"#rxn = 0n1 + 92U235 = 42Mo98 + 54Xe136 + 4 -1e0 + 2 0n1\n",
"\n",
"#Calculation\n",
"LHSm=1.009+m1;\n",
"RHSm=m2+m3+(4*0.00055)+(2*1.009);\n",
"delta_m=LHSm-RHSm; #mass defect(a.m.u)\n",
"E=delta_m*931; #energy released(MeV)\n",
"\n",
"#Result\n",
"print \"mass defect is\",round(delta_m,3),\"a.m.u\"\n",
"print \"energy released is\",int(E),\"MeV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"mass defect is 0.211 a.m.u\n",
"energy released is 196 MeV\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 14.3, Page number 274"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"m1=1.00813; #mass of 1H1(a.m.u)\n",
"m2=4.00386; #mass of 2He4(a.m.u)\n",
"SC=1.35; #solar constant(kW/m^2)\n",
"d=1.5*10**11; #distance b/w earth and sum(m)\n",
"e=1.6*10**-19; #the charge on electron(C)\n",
"Na=6.02*10**26; #Avgraodo no.(per kg mole)\n",
"#rxn = 4 1H1 = 2He4 + 2 1e0\n",
"\n",
"#Calculation\n",
"dm=(4*m1)-m2;\n",
"E=dm*931; #energy produced(MeV)\n",
"EP=E/4; #energy produced per atom(MeV)\n",
"EP=EP*10**6*e; #conversion in J\n",
"EPkg=EP*Na; #energy produced by 1 kg of hydrogen\n",
"SC=SC*1000; #conversion(J/s-m^2)\n",
"SA=4*math.pi*d**2; #surface area of sphere\n",
"ER=SC*SA; #energy recieved per second\n",
"m=ER/EPkg; #mass of hydrogen consumed(tonnes/second)\n",
"\n",
"#Result\n",
"print \"mass of hydrogen consumed is\",round(m/10**11,3),\"*10**8 tonnes/second\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"mass of hydrogen consumed is 5.941 *10**8 tonnes/second\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 14.4, Page number 275"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"m1=2.01478; #mass of 1H2(a.m.u)\n",
"m2=4.00388; #mass of 2He4(a.m.u)\n",
"#rxn 1H2 + 1H2 = 2He4 + Q\n",
"\n",
"#Calculation\n",
"Q=2*m1-m2; #energy liberated(MeV) \n",
"Q=Q*931; #conversion in MeV\n",
"\n",
"#Result\n",
"print \"energy liberated is\",round(Q,1),\"MeV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"energy liberated is 23.9 MeV\n"
]
}
],
"prompt_number": 11
}
],
"metadata": {}
}
]
}
|
