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{
"metadata": {
"name": "",
"signature": "sha256:8d579c32fbc82bfc0d050265719851f3d1a9f6f9fcc17df43ae5b1c38cc41c26"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"2: The Electron"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 2.1, Page number 18"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"E=2400; #electric field intensity(V/m)\n",
"V=90; #potential difference(V)\n",
"e=1.6*10**-19; #the charge on electron(C)\n",
"m=9.12*10**-31; #mass of electron(kg)\n",
"\n",
"#Calculation\n",
"F=e*E; #force on electron(N)\n",
"a=F/m; #acceleration(m/s^2) \n",
"KE=e*V; #Kinetic Energy of particle(J) \n",
"v=math.sqrt(2*KE/m); #velocity of the electron(m/s)\n",
"v=v*10**-6;\n",
"v=math.ceil(v*10**2)/10**2; #rounding off to 2 decimals\n",
"\n",
"#Result\n",
"print \"The force on electron is\",F,\"N\"\n",
"print \"Its acceleration is\",round(a/1e+14,2),\"*10**14 m/s^2\"\n",
"print \"The Kinetic Energy of particle is\",KE,\"J\"\n",
"print \"The velocity of the electron\",v,\"*10**6 m/s\"\n",
"print \"answers for acceleration and velocity given in the book varies due to rounding off errors\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The force on electron is 3.84e-16 N\n",
"Its acceleration is 4.21 *10**14 m/s^2\n",
"The Kinetic Energy of particle is 1.44e-17 J\n",
"The velocity of the electron 5.62 *10**6 m/s\n",
"answers for acceleration and velocity given in the book varies due to rounding off errors\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 2.2, Page number 18"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"V=900; #potential difference(V)\n",
"B=0.01; #uniform magnetic field(Wb/m^2)\n",
"em=1.76*10**11; #value of e/m(C/kg)\n",
"\n",
"#calculation\n",
"v=math.sqrt(2*em*V); #linear velocity of electron(m/s)\n",
"R=v/(em*B); #radius of the circular path(m) \n",
"R=math.ceil(R*10**3)/10**3; #rounding off to 3 decimals\n",
"v=v*10**-7;\n",
"v=math.ceil(v*10**2)/10**2; #rounding off to 2 decimals\n",
"\n",
"#Result\n",
"print \"The linear velocity of electron is\",v,\"*10**7 m/s\"\n",
"print \"The radius of the circular path is\",R,\"m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The linear velocity of electron is 1.78 *10**7 m/s\n",
"The radius of the circular path is 0.011 m\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 2.3, Page number 18"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"d=6*10**-3; #distance between plates(m)\n",
"V=900; #potential difference(V)\n",
"B=0.5; #uniform magnetic field(Wb/m^2)\n",
"Q=1.6*10**-19; #the charge on electron(C)\n",
"R=10.6*10**-2; #circular track radius(m)\n",
"\n",
"#calculation\n",
"v=V/(B*d); #velocity(m/s)\n",
"m=R*Q*B/v; #mass of particle(kg)\n",
"\n",
"#Result\n",
"print \"The mass of particle\",round(m/1e-26,3),\"*10**-26 kg\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The mass of particle 2.827 *10**-26 kg\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example number 2.4, Page number 19"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#import modules\n",
"import math\n",
"from __future__ import division\n",
"\n",
"#Variable declaration\n",
"V=6920; #potential difference(V)\n",
"d=1.3*10**-2; #distance between(m)\n",
"v=1.9*10**-4; #velocity(m/s)\n",
"p=0.9*10**3; #density of oil(kg/m^3)\n",
"n=1.81*10**-5; #coefficient of viscosity(N-s/m^2)\n",
"g=9.81; #accelaration due to gravity(m/s^2)\n",
"\n",
"#calculation\n",
"a=math.sqrt((9*n*v)/(2*g*p)); #radius of the drop(m) \n",
"E=V/d; #electric field(V/m)\n",
"Q=4*math.pi*(a**3)*p*g/(3*E); #value of charge on oil drop(C)\n",
"\n",
"#Result\n",
"print \"The radius of the drop is\",round(a/1e-6,2),\"micro m\"\n",
"print \"The value of charge on oil drop is\",round(Q/1e-19,3),\"*10^-19 C\"\n",
"print \"answers given in the book are wrong\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The radius of the drop is 1.32 micro m\n",
"The value of charge on oil drop is 1.612 *10^-19 C\n",
"answers given in the book are wrong\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
