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{
"metadata": {
"name": "MP-1"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": "Introduction"
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 1.1 Page 12"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nMn=1.008665;Mp=1.007276 #Given mass of an electron and a proton in terms of u\n\n#calculation\nMd= Mn-Mp; #mass difference \nMd2=Md*931.50; #converting u into Mev/c^2 by multiplying by 931.5 MeV/c^2\n\n#result\nprint \"Mass difference in terms of U is\",round(Md,4); \nprint\"which equals in Mev/c^2. :\",round(Md2,3);",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "Mass difference in terms of U is 0.0014\nwhich equals in Mev/c^2. : 1.294\n"
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 1.2 Page 12"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nMp=1.007276 ; Me=5.4858*10**-4; #mass of proton and electron in terms of U\n\n#calculation\nMt=Mp+Me; #Total mass= sum of above masses \n\n#result\nprint\"The combined mass of an electron and a proton was found out to be in U.\",round(Mt,3);\n",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "The combined mass of an electron and a proton was found out to be in U. 1.008\n"
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": "Example 1.3 Page 13"
},
{
"cell_type": "code",
"collapsed": false,
"input": "#initiation of variable\nh=6.621*10**-34 ; c=2.9979*10**8; # h is in J/s and c is in m/s\nhc=h*c*((10**9)/(1.6022*10**-19)); #1e=1.602*10^-19 J and 1 m=10^9 nm\n\n#result\nprint \"The value of hc in eV.nm is\",round(hc,4); \nprint 'Hence zero at the end is significant.';\n",
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": "The value of hc in eV.nm is 1238.8651\nHence zero at the end is significant.\n"
}
],
"prompt_number": 8
}
],
"metadata": {}
}
]
}
|
