1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
|
{
"metadata": {
"name": "Chapter15"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 15:The General Theory of Relativity"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 15.1, Page 491"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initiation of variable\n",
"w=121.5; #lambda\n",
"G=6.67*10**-11; #Various given values and constants\n",
"M= 1.99*10**30; \n",
"R= 6.96*10**8;\n",
"c=3*10**8;\n",
"\n",
"#calculation\n",
"k= G*M/(R*c**2); #(delLambda)/(lambda)\n",
"delw=k*w; #del(lambda)\n",
"\n",
"#result\n",
"print \"The change in wavelength due to gravitational shift in pm is\",round(delw*10**3,3);\n",
"\n",
"#part3\n",
"k=5.5*10**-5;#due to thermal Doppler broadening effect\n",
"delw=k*w;\n",
"\n",
"#result\n",
"print \"The change in wavelength due to thermal Doppler broadening effect in pm is\",round(delw*10**3,3);"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" The change in wavelength due to gravitational shift in pm is 0.257\n",
"The change in wavelength due to thermal Doppler broadening effect in pm is 6.683\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 15.2, Page 501"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initiation of variable\n",
"mp=938.280; #mass of various particles\n",
"me=0.511;\n",
"m2h=1875.628;\n",
"\n",
"#calculation\n",
"mic2=2*mp; #mass energy on L.H.S\n",
"mfc2=m2h+me; #mass energy on R.H.S\n",
"Q=mic2-mfc2; #Q value of reation\n",
"pc=Q;\n",
"mc2=1875.628;\n",
"K=(pc**2)/(2*mc2); #kinetic threshold energy\n",
"Emax=Q-K; #maximum energy \n",
"\n",
"#result\n",
"print \"The maximum neutrino energy in MeV is\",round(Emax,3);"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The maximum neutrino energy in MeV is 0.421\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|