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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 17 Television"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 17.1 Page no 882"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"bw=5*10**6 #bandwidth\n",
"t=53.5*10**-6 #time allocated for each visible trace\n",
"\n",
"#calculation\n",
"T=2*bw*t #increase in horizontal resolution\n",
"\n",
"#result\n",
"print\"Thus, the total number of vertical lines resolvable is \",T,\"lines\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Thus, the total number of vertical lines resolvable is 535.0 lines\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 17.2 Page no 822"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"bw=5.0*10**6 #bandwidth\n",
"l=428 #horizontal resolution\n",
"\n",
"#calculation\n",
"t=l/(bw*2) #trace time\n",
"x=1/30.0 #time available for a full picture\n",
"y=t+10.0*10**-6 #assuming that 10us is used for horizontal blanking\n",
"n=x/y #no. of horizontal traces\n",
"c=600*0.7 #allowing 32 lines for vertical retrace\n",
"\n",
"#result\n",
"print\"vertical resolution = \",c,\"lines\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"vertical resolution = 420.0 lines\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
