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{
"metadata": {
"name": "",
"signature": "sha256:ff1027836ff09444a0f286e9b3a2446de80c3b84e271ae3db6a9354c2ea33b2b"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 4: Shear Forces and Bending Moments"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4.3, page no. 275"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math\n",
"\n",
"#initialisation\n",
"\n",
"q = 0.2 # Uniform load intensity in K/ft\n",
"P = 14 # Concentrated load in k\n",
"Ra = 11 # Reaction at A from wquation of equilibrium\n",
"Rb = 9 # Reaction at B from wquation of equilibrium\n",
"\n",
"#calculation\n",
"V = 11 - 14 - (0.2*15) # shear force in k\n",
"\n",
"print \"Shear force at section D\", V, \"k\"\n",
"M = (11*15)-(14*6)-(0.2*15*7.5) # Bending moment in K-ft\n",
"print \"Bending moment at section D\", M, \"k-ft\"\n",
"V1 = -9+(0.2*15) # Shear firce from alternative method in k\n",
"M1 = (9*9)-(0.2*7.5*15) # Bending moment from alternative method in k-ft"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Shear force at section D -6.0 k\n",
"Bending moment at section D 58.5 k-ft\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 4.7"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math \n",
"\n",
"#initialisation\n",
"\n",
"q = 1 # Uniform load intensity in k/ft\n",
"M0 = 12 # Couple in k-ft\n",
"Rb = 5.25 # Reaction at B in k\n",
"Rc = 1.25 # Reaction at C in k\n",
"b = 4 # Length of section AB in ft\n",
"\n",
"#calculation\n",
"\n",
"Mb = -(q*(b**2))/2 # Moment acting at B\n",
"\n",
"#Result\n",
"print \"Bending moment at B\", Mb, \"k-ft\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Bending moment at B -8 k-ft\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
