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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 1: Introduction"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Example 1.1, Shear Stress, Page No. 16"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Shear Stress Required to nucleate a grain boundary crack in high temperature deformation = 158.887 MPa\n"
]
}
],
"source": [
"#variable declaration\n",
"from math import pi\n",
"from math import sqrt\n",
"y_b=2;\n",
"G=75;\n",
"G=G*10**9; #conversion to Pa\n",
"L=0.01;\n",
"L=L*10**-3; #conversion to m\n",
"nu=0.3;\n",
"\n",
"#calculation\n",
"T=sqrt((3*pi*y_b*G)/(8*(1-nu)*L));\n",
"T=T/10**6;\n",
"\n",
"#result\n",
"print ('Shear Stress Required to nucleate a grain boundary crack in high temperature deformation = %g MPa') %(T)"
]
}
],
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"display_name": "Python 2",
"language": "python",
"name": "python2"
},
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"name": "ipython",
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|
