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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 22 - Combustion Processes : First law analysis"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5 - Pg 419"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the heat transferred from the system\n",
"#initialization of varaibles\n",
"mO=1.33\n",
"CO=0.155\n",
"mC=3.67\n",
"CC=0.165\n",
"t2=1000. #F\n",
"tb=68. #F\n",
"t1=300. #F\n",
"mC2=1.\n",
"CC2=0.17\n",
"mO2=4.\n",
"CO2=0.155\n",
"H=-14087 #B/lb\n",
"#calculations\n",
"dE2=mO*CO*(t2-tb) + mC*CC*(t2-tb)\n",
"dE1=mO2*CO2*(tb-t1) + mC2*CC2*(tb-t1)\n",
"Q=dE2+dE1+H\n",
"#results\n",
"print '%s %d %s' %(\"Heat transfer from the system =\",Q,\"Btu\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Heat transfer from the system = -13513 Btu\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 6 - Pg 422"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the cp value of methane\n",
"#initialization of varaibles\n",
"H1=17889 #Cal/g\n",
"H2=-94052 #Cal/g\n",
"H3=2* -68317 #Cal/g\n",
"#calculations\n",
"x=H1+H2+H3\n",
"#results\n",
"print '%s %d %s' %(\"Constant pressure heating value of methane =\",x,\" cal/gm formula wt.\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Constant pressure heating value of methane = -212797 cal/gm formula wt.\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 7 - Pg 423"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the cv value of methane\n",
"#initialization of varaibles\n",
"HV=4344 #B/lb\n",
"xC=56 #lb\n",
"R=1.986\n",
"T=530 #R\n",
"MC=56 #g/mol\n",
"#calculations\n",
"HR=xC*HV\n",
"Eb=-HR -R*T*(2-3)\n",
"HV=-Eb/MC\n",
"#results\n",
"print '%s %d %s' %(\"COnstant volume heating value =\",HV,\"B/lb \")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"COnstant volume heating value = 4325 B/lb \n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8 - Pg 426"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the products temperature\n",
"#initialization of varaibles\n",
"dH2=14087 #B/lb\n",
"xc=3.67 #lb\n",
"xN=8.78 #lb\n",
"tb=100 #F\n",
"#calculations\n",
"dt2=dH2/(xc*0.196 + xN*0.248)\n",
"t2=dt2+tb\n",
"#results\n",
"print '%s %d %s' %(\"products temperature =\",t2,\"F\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"products temperature = 4963 F\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 9 - Pg 430"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the efficiency\n",
"#initialization of varaibles\n",
"Heat=14087 #Btu/lb\n",
"x1=0.9 #lb\n",
"x2=0.05 #lb\n",
"x3=0.05 #lb\n",
"Heat2=3952 #Btu/lb\n",
"#calculations\n",
"h1=x1*Heat\n",
"h2=x2*Heat2\n",
"e=(h1+h2)/Heat\n",
"#results\n",
"print '%s %.2f' %(\"Efficiency = \",e)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Efficiency = 0.91\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 10 - Pg 431"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the efficiency of the process\n",
"#initialization of varaibles\n",
"print '%s' %(\"From data and steam tables,\")\n",
"Q=10240000. #B/hr\n",
"w=700. #lb/hr\n",
"h=19500. #B/lb\n",
"#calculations\n",
"HV=w*h\n",
"e=Q/HV\n",
"#results\n",
"print '%s %.2f' %(\"Efficiency = \",e)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"From data and steam tables,\n",
"Efficiency = 0.75\n"
]
}
],
"prompt_number": 6
}
],
"metadata": {}
}
]
}
|
