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{
"metadata": {
"name": ""
},
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 15 - Vapor Cycles : More Efficient Cycles"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1 - Pg 243"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the improvement in efficiency\n",
"#initialization of varaibles\n",
"e=0.85\n",
"print '%s' %(\"From Mollier chart and table 3,\")\n",
"h1=1474.5 #B/lb\n",
"s1=1.5603 #B/lb R\n",
"h2s=1277.5 #B/lb\n",
"#calculations\n",
"h2=h1-e*(h1-h2s)\n",
"h3=1522.4 #B/lb\n",
"h4s=948 #B/lb\n",
"h4=h3-e*(h3-h4s)\n",
"h5=47.6 #B/lb\n",
"h6=53.5 #B/lb\n",
"h7s=840 #B/lb\n",
"h7=h1-e*(h1-h7s)\n",
"h8=1493.2 #B/lb\n",
"h9s=866 #B/lb\n",
"h9=h8-e*(h8-h9s)\n",
"h11=51.5 #B/lb\n",
"eta1=0.401\n",
"eta2=0.375\n",
"eta3=0.366\n",
"IE1=(eta1-eta2)/eta2\n",
"IE2=(eta1-eta3)/eta3\n",
"#results\n",
"print '%s %.1f %s' %(\"Improvement in efficiency =\",IE1*100,\"percent\")\n",
"print '%s %.1f %s' %(\"\\nImprovement in efficiency in case 2=\",IE2*100,\"percent\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"From Mollier chart and table 3,\n",
"Improvement in efficiency = 6.9 percent\n",
"\n",
"Improvement in efficiency in case 2= 9.6 percent\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2a - Pg 257"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the fraction of energy supplied \n",
"#initialization of varaibles\n",
"print '%s' %(\"From mollier chart and table 3,\")\n",
"h1=1371. #B/lb\n",
"h2s=1149. #B/lb\n",
"h3=118. #B/lb\n",
"e=0.9\n",
"print '%s' %(\"Neglecting pump work,\")\n",
"Q1=h1-h3\n",
"W=156. #B/lb\n",
"eta1=W/Q1\n",
"Q=h1-W-h3\n",
"UE=W+e*Q\n",
"fraction = UE/Q1\n",
"#results\n",
"print '%s %.2f' %(\"Fraction supplied = \",fraction)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"From mollier chart and table 3,\n",
"Neglecting pump work,\n",
"Fraction supplied = 0.91\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2b - Pg 258"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the fraction of energy supplied \n",
"#initialization of varaibles\n",
"print '%s' %(\"From mollier chart and table 3,\")\n",
"h1=1371. #B/lb\n",
"h2s=1149. #B/lb\n",
"h3=118. #B/lb\n",
"e=0.23\n",
"e2=0.9\n",
"print '%s' %(\"Neglecting pump work,\")\n",
"Q1=h1-h3\n",
"W=156. #B/lb\n",
"eta1=W/Q1\n",
"Q=h1-W-h3\n",
"We=W/e\n",
"UE=We+Q\n",
"UE1=W+e2*Q\n",
"Q2=Q+We\n",
"fraction = UE1/UE\n",
"#results\n",
"print '%s %.2f' %(\"Fraction supplied = \",fraction)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"From mollier chart and table 3,\n",
"Neglecting pump work,\n",
"Fraction supplied = 0.64\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|
