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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 16 - Gas Cycles"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1a - Pg 279"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the efficiency and work done per pound of fluid\n",
"#initialization of varaibles\n",
"import math\n",
"Pb=75. #psia\n",
"Pc=15. #psia\n",
"k=1.4\n",
"Td=550. #R\n",
"Tb=1700. #R\n",
"cp=0.24\n",
"#calculations\n",
"print '%s' %(\"Gas law solution\")\n",
"Pratio=Pb/Pc\n",
"Ta=Td*math.pow((Pratio),((k-1)/k))\n",
"Tc=Tb/math.pow((Pratio),((k-1)/k))\n",
"Q1=cp*(Tb-Ta)\n",
"Q2=cp*(Tc-Td)\n",
"Wnet=Q1-Q2\n",
"eta=Wnet/Q1\n",
"eta2=1-Td/Ta\n",
"#results\n",
"print '%s %.3f' %(\"Efficiency in 1= \",eta)\n",
"print '%s %.2f' %(\"\\n Efficiency in 2 = \",eta2)\n",
"print '%s %d %s' %(\"\\n Work per pound of fluid =\",Wnet,\"B/lb\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Gas law solution\n",
"Efficiency in 1= 0.369\n",
"\n",
" Efficiency in 2 = 0.37\n",
"\n",
" Work per pound of fluid = 73 B/lb\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1b - Pg 280"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#calculate the efficiency and work done per pound of fluid\n",
"#initialization of variables\n",
"import math\n",
"Pb=75. #psia\n",
"Pc=15. #psia\n",
"k=1.4\n",
"Td=550. #R\n",
"Tb=1700. #R\n",
"cp=0.24\n",
"#calculations\n",
"Prd=1.4779\n",
"hd=131.46 #B/lb\n",
"Prb=90.95\n",
"hb=422.59 #B/lb\n",
"Pratio=Pb/Pc\n",
"Pra=Pratio*(Prd)\n",
"Ta=868 #R\n",
"ha=208.41\n",
"Prc=Prb/Pratio\n",
"Tc=1113 #R\n",
"hc=269.27\n",
"Q1=hb-ha\n",
"Q2=hc-hd\n",
"Wnet=Q1-Q2\n",
"eta=Wnet/Q1\n",
"#results\n",
"print '%s %.3f' %(\"Efficiency = \",eta)\n",
"print '%s %.2f %s' %(\"\\n Work per pound of fluid =\",Wnet,\"B/lb\")\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Efficiency = 0.357\n",
"\n",
" Work per pound of fluid = 76.37 B/lb\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 2 - Pg 282"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculate the work done and efficiency of the process\n",
"#initialization of varaibles\n",
"e=0.75\n",
"Ta=870. #R\n",
"Tc=1075. #R\n",
"cp=0.24\n",
"Td=550. #R\n",
"Tb=1700. #R\n",
"#calculations\n",
"Tadash=e*(Tc-Ta) +Ta\n",
"Tcdash=Tc+Ta-Tadash\n",
"Q1=cp*(Tb-Tadash)\n",
"Q2=cp*(Tcdash-Td)\n",
"Wnet=Q1-Q2\n",
"eta=Wnet/Q1\n",
"#results\n",
"print '%s %d %s' %(\"Net work done =\",Wnet,\"B/lb\")\n",
"print '%s %.2f' %(\"\\n efficiency = \",eta)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Net work done = 73 B/lb\n",
"\n",
" efficiency = 0.45\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|
