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{
"metadata": {
"name": "CH8"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 8: Failure"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.1 Page no 217"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"sigma=40*10**6 # in Pa Tensile stress\n",
"E=69*10**9 #Modulus of elaticity in pa\n",
"Ys=0.3 #Specific surface energy in N/m**2\n",
"\n",
"a=2*E*Ys/(math.pi*sigma**2)\n",
"\n",
"print\"Maximum lemgth of a surface flaw without fracture is \",round(a*10**6,1),\"micro m\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Maximum lemgth of a surface flaw without fracture is 8.2 micro m\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Design Example 8.2 Page no 242"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"T=800.0+273.0 # Temperature in K\n",
"\n",
"import math\n",
"L_M=24*10**3\n",
"t=math.pow(10,(L_M/T)-20)\n",
" \n",
"print\"Time to rupture is \",round(t,0),\"h\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Time to rupture is 233.0 h\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
