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{
"metadata": {
"name": "CH16"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 16: Composites"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 16.1 Page No 589"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#(a) Compute the modulus of elasticity\n",
"#(b) find Load carried by each of fiber and matrix phase\n",
"#(c) Determine the strain\n",
"\n",
"#Given\n",
"E_gf=69.0 # in GPa Elasticity of glass fibre\n",
"mf_gf=0.4 #Vol % of glass fibre\n",
"E_pr=3.4 # in GPa Elasticity of poyester resin\n",
"mf_pr=0.6 #Vol % of polyester resin\n",
"\n",
"#Calculation\n",
"E_cl=(E_pr*mf_pr)+(E_gf*mf_gf)\n",
"Ac=250.0 #mm**2\n",
"sigma=50.0 #MPa\n",
"ratio=(E_gf*mf_gf)/(E_pr*mf_pr) # ratio=Ff/Fm\n",
"Fc=Ac*sigma #N\n",
"Fm=Fc/(ratio+1)\n",
"Ff=Fc-Fm\n",
"Am=mf_pr*Ac\n",
"Af=mf_gf*Ac\n",
"sigma_m=Fm/Am\n",
"sigma_f=Ff/Af\n",
"e_m=sigma_m/(E_pr*10**3) #Strain for matrix phase\n",
"e_f=sigma_f/(E_gf*10**3) #Strain for fiber phase\n",
"\n",
"#Result\n",
"print\"(a)Modulus of elasticity of composite is \",round(E_cl,0),\"GPa\"\n",
"print\"(b)Load carried by each of fiber and matrix phase is \",round(Ff,0),\"N\"\n",
"print\"(c)Strain for matrix phase is \",round(e_m,4)\n",
"print\" Strain for fiber phase is \",round(e_f,4)\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)Modulus of elasticity of composite is 30.0 GPa\n",
"(b)Load carried by each of fiber and matrix phase is 11640.0 N\n",
"(c)Strain for matrix phase is 0.0017\n",
" Strain for fiber phase is 0.0017\n"
]
}
],
"prompt_number": 15
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 16.2 Page No 591"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Elastic Modulus Determination for a Glass Fiber-Reinforced Composite\u2014Transverse Direction\n",
"\n",
"#Given\n",
"E_gf=69 # in GPa Elasticity of glass fibre\n",
"mf_gf=0.4 #Vol % of glass fibre\n",
"E_pr=3.4 # in GPa Elasticity of poyester resin\n",
"mf_pr=0.6 #Vol % of polyester resin\n",
"\n",
"#Calculation\n",
"E_ct=E_pr*E_gf/((E_pr*mf_gf)+(E_gf*mf_pr)) #GPa\n",
"\n",
"#Result\n",
"print\"In transverse direction, modulus of elaticity is \",round(E_ct,1),\"GPa\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"In transverse direction, modulus of elaticity is 5.5 GPa\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Design Example 16.1 ,Page No :601"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#A tubular composite shaft is to be designed.\n",
"\n",
"#Given\n",
"Do=70*10**-3 #mm, outside diameter\n",
"Di=50*10**-3 #mm, inside diameter\n",
"L=1 #m Length\n",
"F=1000 #N load\n",
"dy=0.35*10**-3 #mm, deflection\n",
"\n",
"#Calculation\n",
"#Required longitudinal modulus of elasticity\n",
"E=(4*F*L**3)/(3*math.pi*dy*(Do**4-Di**4))\n",
"Vc=(math.pi*L*(Do**2-Di**2))/4.0\n",
"\n",
"#Result\n",
"print\"(a)longitudinal modulus of elasticity is\",round(E/10**9,1),\"GPa\"\n",
"print\"(b)The total tube volume is\",round(Vc*10**6,0),\"cm**3\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)longitudinal modulus of elasticity is 68.3 GPa\n",
"(b)The total tube volume is 1885.0 cm**3\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
