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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 14: Polymer Structure"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 14.1 Page No 499"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Mi1=7500 #g/mol , Molecular wt\n",
"Mi2=12500 \n",
"Mi3=17500\n",
"Mi4=22500\n",
"Mi5=27500\n",
"Mi6=32500\n",
"Mi7=37500\n",
"xi1=0.05 #Number fraction\n",
"xi2=0.16\n",
"xi3=0.22\n",
"xi4=0.27\n",
"xi5=0.2\n",
"xi6=0.08\n",
"xi7=0.02\n",
"\n",
"xM1=Mi1*xi1\n",
"xM2=Mi2*xi2\n",
"xM3=Mi3*xi3\n",
"xM4=Mi4*xi4\n",
"xM5=Mi5*xi5\n",
"xM6=Mi6*xi6\n",
"xM7=Mi7*xi7\n",
"xM=xM1+xM2+xM3+xM4+xM5+xM6+xM7\n",
"\n",
"nC=2 #no of carbon atoms in repeat unit\n",
"nH=3 #no of hydrogen atoms in repeat unit\n",
"nCl=1 #no of chlorine atoms in repeat unit\n",
"MwC=12.01 #Molecular wt of carbon\n",
"MwH=1.01 #Molecular wt of Hydogen\n",
"MwCl=35.45 #Molecular wt of chlorine\n",
"m=nC*MwC+nH*MwH+nCl*MwCl #Total wt for PVC\n",
"DP=xM/m\n",
"\n",
"wi1=0.02 #weight fraction\n",
"wi2=0.1\n",
"wi3=0.18\n",
"wi4=0.29\n",
"wi5=0.26\n",
"wi6=0.13\n",
"wi7=0.02\n",
"\n",
"wM1=Mi1*wi1\n",
"wM2=Mi2*wi2\n",
"wM3=Mi3*wi3\n",
"wM4=Mi4*wi4\n",
"wM5=Mi5*wi5\n",
"wM6=Mi6*wi6\n",
"wM7=Mi7*wi7\n",
"wM=wM1+wM2+wM3+wM4+wM5+wM6+wM7\n",
"\n",
"print\"(a)The no Av Molecular wt is\",xM,\"g/mol\"\n",
"print\"(b)Degree of Polymerisation is\",round(DP,0)\n",
"print\"(c)The weight Av Molecular wt is\",wM,\"g/mol\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)The no Av Molecular wt is 21150.0 g/mol\n",
"(b)Degree of Polymerisation is 338.0\n",
"(c)The weight Av Molecular wt is 23200.0 g/mol\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 14.2 Page No 511"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Ac=12.01 #in g/mol Molecular weight of Carbon\n",
"Ah=1.008 #in g/mol molecular weight of hydrogen\n",
"a=7.41*10**-8 #in cm\n",
"b=4.94*10**-8 #in cm\n",
"c=2.55*10**-8 #in cm\n",
"Na=6.023*10**23\n",
"\n",
"Vc=a*b*c\n",
"n=2\n",
"A=(2*Ac)+(4*Ah)\n",
"density_c=n*A/(Vc*Na)\n",
"\n",
"density_a=0.870 # in g/cm**3\n",
"density_s=0.925 # in g/cm**3\n",
"pc=density_c*(density_s-density_a)*100/(density_s*(density_c-density_a))\n",
"\n",
"print\"(a)Density is\",round(density_c,3),\"g/cm**3\"\n",
"print\"(b)percentage crystallinity is\",round(pc,1),\"%\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)Density is 0.998 g/cm**3\n",
"(b)percentage crystallinity is 46.4 %\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 14.3 Page No 516"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"\n",
"P1=400000.0 # in Pa Pressure inside the bottle\n",
"P2=400.0 # in Pa Pressure outside the bottle\n",
"Pm=0.23*10**-13 #Solubility Coefficient\n",
"dx=0.05 # in cm Thickness of wall\n",
"\n",
"J=(-Pm*(P2-P1)/dx)\n",
"\n",
"A=500 #surface area of bottle in cm**2\n",
"V_lose=750.0 #cm**3 STP\n",
"V=J*A\n",
"t=V_lose/round(V,5)\n",
"\n",
"print\"Diffusion flux is \",round(J,9),\"cm**3 STP/cm**2-s\"\n",
"print\"Time to escape is \",round(t/(3600*24),1),\"days\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Diffusion flux is 1.84e-07 cm**3 STP/cm**2-s\n",
"Time to escape is 96.5 days\n"
]
}
],
"prompt_number": 20
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
