summaryrefslogtreecommitdiff
path: root/Materials_science_and_engineering_an_introduction/CH12.ipynb
blob: b27746987afe7f68e2ce2943037fd6a5b7ac77b9 (plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
{
 "metadata": {
  "name": "CH12"
 },
 "nbformat": 3,
 "nbformat_minor": 0,
 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter 12: Structure and Properties of Ceramics"
     ]
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Example 12.1 Page no 418"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "a=30\n",
      "\n",
      "import math\n",
      "ratio=(1-math.cos(a*math.pi/180.0))/math.cos(a*math.pi/180.0)\n",
      "\n",
      "print\"Cation to anion raio is \",round(ratio,3)\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Cation to anion raio is  0.155\n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Example 12.2 Page no 423"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "r_Fe=0.077  # in nm Radius of iron cation Fe++\n",
      "r_O=0.140  #in nm  Radius of Oxygen anion O--\n",
      "\n",
      "ratio=r_Fe/r_O\n",
      "\n",
      "print\"Ratio is \",ratio\n",
      "if 0.414<ratio<0.732:  \n",
      "    print\"Co-ordinaton no. is 6\"\n",
      "    print\"Structure is Rock Salt type\"\n",
      "else:\n",
      "    print \"Coordination no is not 6\"\n",
      "    \n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Ratio is  0.55\n",
        "Co-ordinaton no. is 6\n",
        "Structure is Rock Salt type\n"
       ]
      }
     ],
     "prompt_number": 16
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Example 12.3 Page no 424"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "A_Na=22.99         # in g/mol\n",
      "A_Cl=35.45          #in g/mol\n",
      "r_Na=0.102*10**-7  #in cm Radius of Na+ ion\n",
      "r_Cl=0.181*10**-7  #in cm Radius of Cl- ion\n",
      "Na=6.023*10**23  #Avogadro number\n",
      "\n",
      "a=2*(r_Na+r_Cl)\n",
      "V=a**3\n",
      "n=4                 #For FCC, no. of atoms are 4 per crystal\n",
      "density=n*(A_Na+A_Cl)/(V*Na)\n",
      "\n",
      "print\"Density is \",round(density,2),\"gm/cm**3\"\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Density is  2.14 gm/cm**3\n"
       ]
      }
     ],
     "prompt_number": 18
    },
    {
     "cell_type": "heading",
     "level": 3,
     "metadata": {},
     "source": [
      "Example 12.4 Page no 436"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "Na=6.023*10**23   #Avogadro number\n",
      "density=1.955     #in g/cm**3\n",
      "A_K=39.1          #in g/mol\n",
      "A_Cl=35.45        #in g/mol\n",
      "\n",
      "import math\n",
      "N=Na*density*10**6/(A_K+A_Cl)\n",
      "Qs=2.6           # in eV\n",
      "k=8.62*10**-5    # in eV/K  Boltzmann Constant\n",
      "T=500.0+273.0        # in K\n",
      "Ns=N*math.exp(-Qs/(2*k*T))\n",
      "\n",
      "print\"No. of Schottky Defects are \",round(Ns,-17),\"/m**3\"\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "No. of Schottky Defects are  5.31e+19 /m**3\n"
       ]
      }
     ],
     "prompt_number": 26
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [],
     "language": "python",
     "metadata": {},
     "outputs": []
    }
   ],
   "metadata": {}
  }
 ]
}