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{
"metadata": {
"name": "",
"signature": "sha256:dd88e5202fe8cb4f62cee212896e4620a6a485517d90fb3c0293ab4baa871eef"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter02: Structure of atoms"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.1:pg-12"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 2.1 : radius of the first bohr\"s orbit \n",
" \n",
"#given data :\n",
"\n",
"ep=8.854*10**-12;#\n",
"h=6.626*10**-34;#\n",
"m=9.1*10**-31;#in Kg\n",
"e=1.602*10**-19;#\n",
"r1=((ep*(h**2))/((math.pi*m*(e**2))));#\n",
"print round(r1*10**10,2),\"is radius,r1(in angstrom) \"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"0.53 is radius,r1(in angstrom) \n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.2:pg-12"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"#Example 2.2 : radius of the second bohr\"s orbit \n",
" \n",
"#given data :\n",
"\n",
"r1_h=0.529; # radius for hydrozen atom in Angstrum\n",
"n1=1;# for the first bohr's orbit of electron in hydrozen atom\n",
"Z1=1; # for the first bohr's orbit of electron in hydrozen atom\n",
"k=(r1_h*Z1)/n1**2; # where k is constant\n",
"n2=2; # for the second bohr orbit\n",
"Z2=2; #for the second bohr orbit\n",
"r2_he=k*(n2**2/Z2);\n",
"print r2_he,\" is radius of the second bohr orbit,r2 in (Angstrom) \"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"1.058 is radius of the second bohr orbit,r2 in (Angstrom) \n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.3:pg-13"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Example 2.3: to prove\n",
" \n",
"Z=1;#assume\n",
"n1=1;#orbit 1\n",
"n2=2;#orbit 2\n",
"n3=3;#orbit 3\n",
"e1=((-13.6*Z)/(n1**2));#energy for the first orbit\n",
"e2=((-13.6*Z)/(n2**2));#energy for the second orbit\n",
"e3=((-13.6*Z)/(n3**2));#energy for the third orbit\n",
"e31=e3-e1;#energy emitted by an electron jumping from orbit nuber 3 to orbit nimber 1\n",
"e21=e2-e1;#energy emitted by an electron jumping from orbit nuber 2 to orbit nimber 1\n",
"re=e31/e21;#ratio of energy\n",
"print re,\" is equal to ratio of energy for an electron to jump from orbit 3 to orbit 1 and from orbit 2 to orbit 1 is 32/27 \\n hence proved\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"1.18518518519 is equal to ratio of energy for an electron to jump from orbit 3 to orbit 1 and from orbit 2 to orbit 1 is 32/27 \n",
" hence proved\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.4:pg-13"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 2.4 : velocity\n",
" \n",
"#given data :\n",
"\n",
"h=6.626*10**-34;\n",
"e=1.6*10**-19;\n",
"epsilon_o=8.825*10**-12;\n",
"n=1;\n",
"Z=1;\n",
"vn=(Z*e**2)/(2*epsilon_o*n*h);\n",
"print vn,\" is velocity,vn in (m/s) \"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"2188990.2342 is velocity,vn in (m/s) \n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.5:pg-14"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 2.5 : velocity\n",
" \n",
"#given data :\n",
"n=1;\n",
"Z=1;\n",
"k=6.56*10**15; # k is constant\n",
"fn=k*(Z**2/n**3);\n",
"print fn,\" is orbital frequency,fn in (Hz) \"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"6.56e+15 is orbital frequency,fn in (Hz) \n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.6.a:pg-14"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 2.6.a : the energy of the photon emitted\n",
" \n",
"#given data :\n",
"Z=1;#for hydrozen\n",
"n1=3;\n",
"n2=2;\n",
"E3=-(13.6*Z**2)/n1**2;\n",
"E2=-(13.6*Z**2)/n2**2;\n",
"del_E=E3-E2;\n",
"print round(del_E,2),\" is the energy of photon emitted, del_E in (eV) \"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"1.89 is the energy of photon emitted, del_E in (eV) \n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.6.b:pg-14"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 2.6.b : frequency\n",
" \n",
"#given data :\n",
"\n",
"Z=1;#for hydrozen\n",
"n1=3;\n",
"n2=2;\n",
"m=6.626*10**-34;# mass of electron in kg\n",
"E3=-(13.6*Z**2)/n1**2;\n",
"E2=-(13.6*Z**2)/n2**2;\n",
"del_E=E3-E2;\n",
"E=del_E*1.6*10**-19;# in joules\n",
"v=(E/m);\n",
"print round(v,2),\"frequency of the photon emitted,v(Hz) \"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"4.5611563873e+14 frequency of the photon emitted,v(Hz) \n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2.6.c:pg-15"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Example 2.6.c : wave length of the photon emitted\n",
" \n",
"#given data :\n",
"\n",
"Z=1;#for hydrozen\n",
"n1=3;\n",
"n2=2;\n",
"m=6.626*10**-34;# mass of electron in kg\n",
"C=3*10**8;\n",
"E3=-(13.6*Z**2)/n1**2;\n",
"E2=-(13.6*Z**2)/n2**2;\n",
"del_E=E3-E2;\n",
"E=del_E*1.6*10**-19;\n",
"v=E/m;\n",
"lamda=C/v;\n",
"print round(lamda,9),\" is wavelength of the photon emitted,(m) \"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"6.58e-07 is wavelength of the photon emitted,(m) \n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}
|
