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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 12 : Heat Treatment"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 12.1 page no : 304"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"# Variables\n",
"n_bcc = 1./2;\n",
"n_fcc = 1./4;\n",
"r_fcc = 1.26;\t\t\t#in Angstorm\n",
"r_bcc = 1.24;\t\t\t#in Angstorm\n",
"\n",
"# Calculations\n",
"a_bcc = 4.*r_bcc/math.sqrt(3);\t\t\t#in Angstorm\n",
"a_fcc = 2.*math.sqrt(2)*r_fcc;\t\t\t#in Angstorm\n",
"v_fcc = a_fcc**3;\n",
"v_bcc = a_bcc**3;\n",
"v = 100*((n_fcc*v_fcc)-(n_bcc*v_bcc))/(n_fcc*v_fcc);\n",
"\n",
"# Results\n",
"print \"Percentage change in volume = %.3f\"%v\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Percentage change in volume = -3.764\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 12.3 pageno : 317"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"e = 51.;\t\t\t#Young modulous in GPa\n",
"v = 0.22;\t\t\t#poisson ratio\n",
"\n",
"# Calculations\n",
"g = e/(2*(1-v));\t\t\t#shear modulous in GPa\n",
"b = 2*10.**-10;\n",
"ue = (1./2)*g*10**9*b**2*10**12;\t\t\t#in J/m**3\n",
"\n",
"# Results\n",
"print \"Change in free energy during recrysatllization (in J/m**3) = %.1f J/m**3\"%ue\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Change in free energy during recrysatllization (in J/m**3) = 653.8 J/m**3\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 12.5 pageno : 329"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"# Variables\n",
"g = 41.*10**9;\t\t\t#in N/m**2\n",
"b = 0.64*10**-9;\t\t\t#in m\n",
"l = 20.*10**-6;\t\t\t#in m\n",
"\n",
"# Calculations\n",
"t = g*b/l;\t\t\t#in N/m**2\n",
"T = t*10.**-6;\t\t\t#in MPa\n",
"\n",
"# Results\n",
"print \"Contribution of these particles (in MPa) = %.3f MPa\"%T\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Contribution of these particles (in MPa) = 1.312 MPa\n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}
|
