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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 14: Luminescence"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 14.1, page no-385"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Penetration depth of electron\n",
"\n",
"import math\n",
"#Variable Declaration\n",
"eb=10000.0 # Energy of incident beam in eV\n",
"k=1.2*10**-4 # Constant depending on marerial \n",
"b=0.151 # Constant depending on marerial\n",
"e=1.6*10**-19 # charge of an electron\n",
"\n",
"#Calculation\n",
"rc=k*(eb*e)**b\n",
"\n",
"#Result\n",
"print('The penetration depth of the electron is %.4f \u00b5m'%(rc*10**6))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The penetration depth of the electron is 0.6998 \u00b5m\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 14.2, page no-386"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Luminescent lifetime\n",
"\n",
"import math\n",
"#Variable Declaration\n",
"ed=0.4 # difference in energy level in eV\n",
"e=1.6*10**-19 # Charge of an electron\n",
"kT=0.025 # temperature equivalent \n",
"q=10**8 # constant\n",
"\n",
"#Calculation\n",
"r=q*math.e**(-(ed/kT))\n",
"\n",
"#Result\n",
"print('The escape rate per unit time = %.1f per sec\\nTherefore, the luminescent lifetime is nearly %.0f sec'%(math.floor(r*10)/10,r))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The escape rate per unit time = 11.2 per sec\n",
"Therefore, the luminescent lifetime is nearly 11 sec\n"
]
}
],
"prompt_number": 5
}
],
"metadata": {}
}
]
}
|
