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{
"metadata": {
"name": "",
"signature": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Ch-7, Manufacturing in the twenty-first century:micromachining, generatice manufacturing, and self assembly"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 1 on page no. 432"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given that\n",
"F = 4e-6 # Maximum feature dimension in meter\n",
"t = 5e-6 # Photorist thickness in meter\n",
"g = 25e-6 # Allowable gap between the mask and the resist meter\n",
"lamda = (F**2)/(t+g)\n",
"print \"Maximum allowable wavelength of the exposing light = %d nm\"%(lamda*(10**9))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Maximum allowable wavelength of the exposing light = 533 nm\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 2 on page no. 440"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"from math import exp\n",
"# Given that\n",
"d = 5 # Diameter of hole in micro meter\n",
"h = 100 # Depth of hole in micro meter\n",
"t = 31.58*(d*(exp(h/(60*d))-1))\n",
"print \"Time required to machine the hole = %0.1f min\"%(t)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Time required to machine the hole = 62.5 min\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 3 on page no. 448"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from math import sqrt\n",
"# Given that\n",
"J = 2 # The threshold value of dose in kJ/cm**3\n",
"h = 300 # Height in micro meter\n",
"J_o = J*(exp(0.1*sqrt(h)))\n",
"print \"The minimum level of exposure of the PMMA surface = %0.1f kJ/cm**3\"%(J_o)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The minimum level of exposure of the PMMA surface = 11.3 kJ/cm**3\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|