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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 8 - 555 Timer "
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.1 Page No.315"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given data \n",
"\n",
"R = 100*10**3\n",
"T = 100*10**-3\n",
"\n",
"# Solution \n",
"\n",
"C = T/(1.1*R)\n",
"\n",
"print \"The value of C =\",round(C*10**6,1),\"uF\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of C = 0.9 uF\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 8.2 Page No.322"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given Data\n",
"\n",
"Ra = 6.8*10**3\n",
"Rb = 3.3*10**3\n",
"C = 0.1*10**-6\n",
"\n",
"# Solution \n",
"# Solution of part a\n",
"\n",
"tHIGH = round(0.69*(Ra + Rb)*C,5)*10**3\n",
"\n",
"# Solution pf part b\n",
"\n",
"tLOW = round(0.69*(Rb)*C,5)*10**3\n",
"\n",
"# Solution of part c\n",
"\n",
"f = int(1.45/((Ra + 2*Rb)*C))*10**-3\n",
"\n",
"# Solution for part d\n",
"\n",
"D = round(Rb/(Ra + 2*Rb),2)\n",
"\n",
"\n",
"# Displaying the answers \n",
"\n",
"print \"The value of tHIGH =\",tHIGH,\"ms\"\n",
"print \"The value of tLOW =\",tLOW,\"ms\"\n",
"print \"The value of frequency f =\",f,\"kHz\"\n",
"print \"The value of Duty cycle D =\",D,\"or\",D*100,\"%\" \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of tHIGH = 0.7 ms\n",
"The value of tLOW = 0.23 ms\n",
"The value of frequency f = 1.082 kHz\n",
"The value of Duty cycle D = 0.25 or 25.0 %\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
