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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 3 : Operational Amplifier Characteristics "
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.1 Page No.108"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given data \n",
"\n",
"Ri = 10*10**3\n",
"R1 = 10*10**6\n",
"Acl = 10\n",
"\n",
"# Solution \n",
"\n",
"Rf = Acl * R1\n",
"Rt = 47*10**3\n",
"Rs = (Rt**2)/(Rf - (2*Rt))\n",
"\n",
"# Displaying the results\n",
"\n",
"print \"The value of Rf = \",Rf/10**6,\"Mega Ohms\"\n",
"print \"Thevalue of Rs = \",Rs,\"Ohms\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Rf = 100 Mega Ohms\n",
"Thevalue of Rs = 22 Ohms\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.2 Page No.110"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given data\n",
"\n",
"Rf = 10*10**3\n",
"R1 = 10**3\n",
"Vios = 10*10**-3\n",
"Ib = 300*10**-9\n",
"Ios = 50*10**-9\n",
"\n",
"# Solution \n",
"# Solution for part a\n",
"Vot1 = (1 + (Rf/R1))*Vios + Rf*Ib\n",
"# Solution for part b \n",
"Rcomp = (Rf * R1)/(Rf + R1)\n",
"# Solution for part c\n",
"Vot2 = (1+(Rf/R1))*Vios + Rf*Ios \n",
"\n",
"# Displaying the values \n",
"\n",
"print \"The value of maximum output offset due to Vios and Ib = \", int( Vot1*10**3),\"mV\"\n",
"print \"The value of Rcomp = \",Rcomp,\"Ohms\" # Given answer in the textbook is not correct please make the change \n",
"print \"The value of maximum output offset if Rcomp is connected = \",Vot2*10**3,\"mV\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of maximum output offset due to Vios and Ib = 113 mV\n",
"The value of Rcomp = 909 Ohms\n",
"The value of maximum output offset if Rcomp is connected = 110.5 mV\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.3 Page No.111"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given data \n",
"\n",
"Acl = 100\n",
"Temp0 = 25\n",
"Temp1 = 50\n",
"Vodrift = 0.15*10**-3\n",
"\n",
"# Solution \n",
"\n",
"Vos = Vodrift * (Temp1 - Temp0)\n",
"Vo = Vos * Acl\n",
"\n",
"# Displaying the results \n",
"\n",
"print \"The value of Input offset voltage = \",Vos*10**3,\"mV\"\n",
"print \"The value of Ooutput voltage = \",int(Vo*10**3),\"mV\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Input offset voltage = 3.75 mV\n",
"The value of Ooutput voltage = 375 mV\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.4 Page No.125"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given data \n",
"from scipy import signal\n",
"import matplotlib.pyplot as plt\n",
"import numpy as np\n",
"\n",
"Vpp = 6.0\n",
"Frequency = 2*10**6\n",
"\n",
"# Solution \n",
"\n",
"WL = 1.0/Frequency # Calculating the wavelength \n",
"SR = Vpp/(WL/2) # Calculating the slew rate\n",
"\n",
"# Displaying the results \n",
"\n",
"print \"The value of slew rate is =\",int(SR*10**-6),\"V/us\"\n",
"\n",
"# Ploting the result \n",
"\n",
"Vp = 3\n",
"t = np.linspace(0, 1, 500)\n",
"plt.plot(t, -Vp*abs(signal.sawtooth(2 * np.pi * 2 * t))) # Note : Triangular wave is the absolute of sawtooth wave\n",
"plt.ylim(-3,0)\n",
"plt.title(\"Output wave form of example 3.4\")\n",
"plt.ylabel(\"Amplitude (V)\")\n",
"plt.xlabel(\"Time(t)\")\n",
"plt.show()"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of slew rate is = 24 V/us\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.5 Page No.126"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"# Given data \n",
"\n",
"Acl = 50\n",
"Slew_rate = 0.5\n",
"frequency = 20*10**3\n",
"# solution \n",
"\n",
"Vm = round((Slew_rate * 10**6)/(2*math.pi * frequency),2)\n",
"Vo = 2 * Vm\n",
"Vpeak_to_peak = Vo/Acl\n",
"\n",
"# Displaying the outputs \n",
"\n",
"print \"The peak voltage is =\",Vm,\"V peak\"\n",
"print \"The peak to peak voltage =\",Vo,\"V peak to peak\"\n",
"print \"The value of maximum input voltage is =\",int(Vpeak_to_peak*10**3),\"mVpeak to peak \" \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The peak voltage is = 3.98 V peak\n",
"The peak to peak voltage = 7.96 V peak to peak\n",
"The value of maximum input voltage is = 159 mVpeak to peak \n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.6 Page No.127"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Given data \n",
"\n",
"Vptpi = 500*10**-3 #input peak to peak voltage \n",
"Vptpo = 3\n",
"Tr = 4*10**-6\n",
"\n",
"# Solution \n",
"\n",
"Vdelta = (0.9 - 0.1) * Vptpo\n",
"SR = (Vdelta / Tr ) * 10**-6\n",
"\n",
"# Display the values \n",
"\n",
"print \"The value of delta V = \",Vdelta,\"V\"\n",
"print \"The slew rate is = \",SR,\"V/us\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of delta V = 2.4 V\n",
"The slew rate is = 0.6 V/us\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}
|
