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{
"metadata": {
"name": "",
"signature": "sha256:1ede18939970cf3dcd5883a4a0c1fb987d10a2324079f20686384266546536c0"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter1, Thyristors"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.11.1 : page 1-29 "
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"#peak reverse recovery current\n",
"#given data :\n",
"itt=10 # time in micro seconds\n",
"qtt=150 #charge in micro colums\n",
"prrc=((2*qtt)/itt) #peak reverse recovery current in amperes\n",
"print \"Peak reverse recovery current = %0.f A\" %prrc"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Peak reverse recovery current = 30 A\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Examples 1.18.1: page 1-44"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"from math import pi, sqrt, cos\n",
"#voltage of the capacitor\n",
"r=10 #in ohms\n",
"l=10 #/inductance in mH\n",
"c=10 #capacitance in micro farads\n",
"v=100 #in volts\n",
"t=((pi)/(sqrt((1/(l*10**-3*c*10**-6))-(r**2/(4*(l*10**-3)**2))))) # time in seconds\n",
"vc= v*(1-cos(t/(sqrt(l*10**-3*c*10**-6))*pi/180)) #in volts\n",
"print \"The capacitor voltage = %0.2f V\" %vc\n",
"#answer is wrong in the textbook"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The capacitor voltage = 0.15 V\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.18.2: page 1-45"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"from math import pi, sqrt, cos\n",
"#voltage of the capacitor\n",
"r=15 #in ohms\n",
"l=12 #/inductance in mH\n",
"c=8 #capacitance in micro farads\n",
"v=100 #in volts\n",
"t=((pi)/(sqrt((1/(l*10**-3*c*10**-6))-(r**2/(4*(l*10**-3)**2))))) # time in seconds\n",
"vc= v*(1-cos(t/(sqrt(l*10**-3*c*10**-6))*pi/180)) #in volts\n",
"print \"The capacitor voltage = %0.2f V\" %vc\n",
"#this question is not solved in the textbook"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The capacitor voltage = 0.16 V\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.20.1: page 1-52"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"#Turn Off Time\n",
"#given data :\n",
"Vs=200 #in volts\n",
"R1=10 # in ohm\n",
"R2=R1 \n",
"C=5 # in micro-farad\n",
"Tc=(R1*C)/1.44 \n",
"print \"The Circuit Turn Off Time, Tc = %0.2f micro-sec\" %Tc"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The Circuit Turn Off Time, Tc = 34.72 micro-sec\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.20.2: page 1-52"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"#Peak Current and turn off time\n",
"#given data :\n",
"Vs=200 #in volts\n",
"R1=10 # in ohm\n",
"R2=R1 \n",
"Vc=200 #in volts\n",
"C=10 # in micro-farad\n",
"I1=Vs/R1 \n",
"I2=(Vs+Vc)/R2 \n",
"It1=I1+I2 \n",
"print \"Peak Current, It1 = %0.2f A \" %It1\n",
"Tc=(R1*C)/1.44 \n",
"print \"The Circuit Turn Off Time, Tc = %0.2f micro-sec \" %Tc"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Peak Current, It1 = 60.00 A \n",
"The Circuit Turn Off Time, Tc = 69.44 micro-sec \n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.21.1: page 1-59"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from __future__ import division\n",
"from math import pi\n",
"#L and C\n",
"#given data :\n",
"V=100 # in volts\n",
"Irm=40 # in A\n",
"tq=40 # in micro-sec\n",
"Del_t=(50/100)*tq # in micro-sec\n",
"C=(Irm*(tq+Del_t))/V \n",
"print \"Capacitance, C = %0.f micro-farad \" %C\n",
"L_min=(V/Irm)**2*C \n",
"print \"Minimum inductance, L_min = %0.f micro-Henry\" %L_min\n",
"T=2.5 # assume one cycle period in ms\n",
"L_max=((0.01*(T*10**-3)**2)/(pi**2*C*10**-6))*10**6 \n",
"print \"Maximum inductance, L_max = %0.2f micro-Henry \" %L_max"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Capacitance, C = 24 micro-farad \n",
"Minimum inductance, L_min = 150 micro-Henry\n",
"Maximum inductance, L_max = 263.86 micro-Henry \n"
]
}
],
"prompt_number": 6
}
],
"metadata": {}
}
]
}
|
