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{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 3:Atomic Spectra-III"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:4,Page no:485"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"R=109729.0 #(cm-1)\n",
"T1=43487.0 #(cm-1)\n",
"T2=28583.0 #(cm-1)\n",
"n=2.0\n",
"\n",
"#calculation\n",
"import math\n",
"delta=n-math.sqrt(R/T2) #quantum defect\n",
"\n",
"#Result\n",
"print\"\\nquantum defect =\",round(delta,4)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"quantum defect = 0.0407\n"
]
}
],
"prompt_number": 15
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:5,Page no:485"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"R=109737 #(cm-1)\n",
"n=1.805 #effective quantum number for the ground state of rubidium\n",
"\n",
"#calculation\n",
"T=R/(8065*n**2) #ionization potential of rubidium (eV)\n",
"\n",
"#Result\n",
"print\"The ionization potential of rubidium =\",round(T,3),\"eV\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The ionization potential of rubidium = 4.176 eV\n"
]
}
],
"prompt_number": 43
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:6,Page no:485"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"ratio=2.5 #ratio of ionization potential of hydrogen and sodium\n",
"n=3.0\n",
"\n",
"#calculation\n",
"import math\n",
"z=math.sqrt(n**2/ratio) #effective atomic number of sodium\n",
"\n",
"#Result\n",
"print\"\\nEffective atomic number of sodium =\",round(z,2)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"Effective atomic number of sodium = 1.9\n"
]
}
],
"prompt_number": 44
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:7,Page no:485"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"hc=12400.0 #value of product of plank's constant and speed of light (eV \u00c5)\n",
"E1=3.18 #separation of 4s and 3s level (eV)\n",
"lembda=5890.0 #wavelength of the first member of principal series of sodium (\u00c5)\n",
"\n",
"#calculation\n",
"E2=round(hc/lembda,1) #separation of 3s and 3p levels (eV)\n",
"deltaE=E1-E2 #separation of 4s and 3p level (eV)\n",
"lembda1=hc/deltaE #wavelength of the first member of sharp series (\u00c5)\n",
"\n",
"#Result\n",
"print\"\u03bb =%d\"%lembda1,\"\u00c5\" \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\u03bb =11481 \u00c5\n"
]
}
],
"prompt_number": 45
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:8,Page no:486"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"lembda1=5890*10**-10 #wavelength of doublet (\u00c5)\n",
"lembda2=5896*10**-10 #wavelength of doublet (\u00c5)\n",
"h=6.63*10**-34 #Plank's constant (Js)\n",
"c=3*10**8 #speed of light (m/s)\n",
"e=1.6*10**-19 #Charge of electron (coulombs)\n",
"\n",
"#calculation\n",
"deltaV=(lembda2-lembda1)/(lembda1*lembda2) #wave no. (m-1)\n",
"deltaE=(h*c*deltaV)/e #separation of energy levels (eV)\n",
"\n",
"#Result\n",
"print\"\u0394E =%.2e\"%deltaE,\"eV\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\u0394E =2.15e-03 eV\n"
]
}
],
"prompt_number": 46
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:9,Page no:486"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"deltaT=2.1*10**-3 #(eV)\n",
"lembda=5893*10**-8 #(\u00c5)\n",
"\n",
"#calculation\n",
"deltaV=deltaT*8065 #(cm-1)\n",
"deltalembda=deltaV*lembda**2 #(cm)\n",
"\n",
"#Result\n",
"print\"\u0394\u03bb =%.2e\"%deltalembda,\"cm\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\u0394\u03bb =5.88e-08 cm\n"
]
}
],
"prompt_number": 47
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:10,Page no:486"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"E1=16960.0 #mean position of the level (cm-1)\n",
"E2=24490 #convergence limit of sharp series (cm-1)\n",
"\n",
"#calculation\n",
"I=(E1+E2)/8065.0 #ionization energy of sodium atom (eV)\n",
"\n",
"#Result\n",
"print\"I =\",round(I,4),\"eV\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"I = 5.1395 eV\n"
]
}
],
"prompt_number": 48
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:11,Page no:486"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"E1=41450.0 #principal series for sodium atom (cm-1)\n",
"E2=24477.0 #sharp series for sodium atom (cm-1)\n",
"\n",
"#calculation\n",
"I=(E1)/8065.0 #ionization energy of sodium atom (eV)\n",
"\n",
"print\"\\nI =\",round(I,3),\"eV\" \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"I = 5.139 eV\n"
]
}
],
"prompt_number": 49
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:12,Page no:487"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"E1=14904 #mean position of the level (cm-1)\n",
"E2=28583 #convergence limit of sharp series (cm-1)\n",
"\n",
"#calculation\n",
"I=(E1+E2)/8065.0 #ionization energy of Li atom (eV)\n",
"\n",
"#Result\n",
"print\"I =\",round(I,2),\"eV\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"I = 5.39 eV\n"
]
}
],
"prompt_number": 50
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:13,Page no:487"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"R=109734 #(cm-1)\n",
"T=24477.0 #(cm-1)\n",
"Zeff=1\n",
"n=3\n",
"\n",
"#calculation\n",
"import math\n",
"delta=n-(Zeff*math.sqrt(R/T)) #quantum defect for 3p configuration of sodium\n",
"\n",
"#Result\n",
"print\"\\n\u0394 =\",round(delta ,3)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"\u0394 = 0.883\n"
]
}
],
"prompt_number": 51
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:14,Page no:487"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Variable declaration\n",
"z1=1.0 #atomic no.\n",
"z2=2.0 #atomic no.\n",
"deltaT2=5.84 #doublet splitting of the first excited state for z=2 (cm-1)\n",
"\n",
"#calculation\n",
"deltaT1=deltaT2*(z1/z2)**4 #separation in hydrogen atom (cm-1)\n",
"\n",
"#Result\n",
"print\"Separation in hydrogen atom =\",deltaT1,\"cm**-1\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Separation in hydrogen atom = 0.365 cm**-1\n"
]
}
],
"prompt_number": 42
}
],
"metadata": {}
}
]
}
|
