1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
|
{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 03 : Junction diode characteristics"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.1, Page No 62"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Na=10.0**19 #Cm^3\n",
"q=1.6*10**-19\n",
"Vj=0.94 #V\n",
"Nd=10.0**17\n",
"e=11.9*8.85*10**-14\n",
"A=9.6*10**-8\n",
"\n",
"#Calculations\n",
"W=math.sqrt(((2*e)/(q*Nd))*Vj)\n",
"Ct=e*A/(W*10**-4)\n",
"\n",
"#Results\n",
"print(\"The transition capacitance is= %.2f fF \" %(Ct*10**11))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The transition capacitance is= 9.09 fF \n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.3, Page No 67"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"t=10 #ns lifetime of holes\n",
"I=0.1 #mA forward current\n",
"n=1\n",
"vt=0.026 #V\n",
"\n",
"#Calculations\n",
"Cd=(t*I)/(n*vt)\n",
"\n",
"#Results\n",
"print(\"The defusion capicitance is= %.2f pF \" %Cd)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The defusion capicitance is= 38.46 pF \n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 3.4, Page No 70"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"V=10.0\n",
"Vb=6.0 # breakdown voltage\n",
"\n",
"vz1=0.1/(0.1+1)*10 #v\n",
"vz2=9.0/(9+1)*10 #v\n",
"\n",
"#Calculations\n",
"Ir=(V-Vb)/vz1\n",
"Il=Vb/vz2\n",
"Iz=Ir-Il\n",
"\n",
"\n",
"#Results\n",
"print(\"The value of Iz is= %.2f mA \" %(Iz))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Iz is= 3.73 mA \n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}
|
